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MAXImum [283]
1 year ago
7

What is the probability of the occurrence of a number that is odd or less than 5

Mathematics
2 answers:
yaroslaw [1]1 year ago
6 0

Answer:

Hence the probability of getting a number less than 5 is 2/3.

Step-by-step explanation:

borishaifa [10]1 year ago
3 0

Answer:

5/6.

Step-by-step explanation:

There are 6 possible outcomes when a fair die is rolled.

The outcomes when the number is odd or less than 5

= 1, 3, 5, 2, 4  (5 outcomes).

So the required probability

= 5/6.

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Six times a number is decreased by 5, the result is 19.what is the number?
marishachu [46]
Simple...

6x-5=19

x= 19+5
 = 24
x= 24/6
  = 4

Thus, your answer is 4.

Hope This Helps!
6 0
3 years ago
A fishing boat was out to sea for six months and traveled a total of 8,579 miles.In the first month the boat traveled 659 miles.
jeka57 [31]
<span>The fishing boat traveled (8579-659)=7920 miles during the remaining 5 months</span>
6 0
2 years ago
) All human blood can be typed as one of O, A, B, or AB. The distribution of the type varies a bit with race. For African-Americ
ivann1987 [24]

Answer:

The correct option is 1 - [(0.8)¹⁰+10*0.2*(0.8)⁹]= 0.6242

Step-by-step explanation:

Hello!

Given the distribution of probabilities for blood types for African-Americans:

O: 0.4

A: 0.2

B: 0.32

AB: 0.08

A random sample of 10 African-American is chosen, what is the probability that 2 or more of them have Type A blood?

Let X represent "Number of African-Americans with Type A blood in a sample of 10.

Then you have two possible outcomes,

"Success" the person selected has Type A blood, with an associated probability p= 0.2

"Failure" the selected person doesn't have Type A blood, with an associated probability q= 0.8

(You can calculate it as "1-p" or adding all associated probabilities of the remaining blood types: 0.4+0.32+0.08)

Considering, that there is a fixed number of trials n=10, with only two possible outcomes: success and failure. Each experimental unit is independent of the rest and the probability of success remains constant p=0.2, you can say that this variable has a Binomial distribution:

X~Bi(n;p)

You can symbolize the asked probability as:

P(X≥2)

This expression includes the probabilities: X=2, X=3, X=4, X=5, X=6, X=7, X=8, X=9, X=10

And it's equal to

1 - P(X<2)

Where only the probabilities of X=0 and X=1 are included.

There are two ways of calculating this probability:

1) Using the formula:

P(X)= \frac{n!}{(n-X)!X!} *p^{x} * q^{n-x}

With this formula, you can calculate the point probability for each value of X=x₀ ∀ x₀=1, 2, 3, 4, 5, 6, 7, 8, 9, 10

So to reach the asked probability you can:

a) Calculate all probabilities included in the expression and add them:

P(X≥2)= P(X=2) + P(X=3) + P(X=4) + P(X=5) + P(X=6) + P(X=7) + P(X=8) + P(X=9) + X=10

b) Use the complement rule and calculate only two probabilities:

1 - P(X<2)= 1 - [P(X=0)+P(X=1)]

2) Using the tables of the binomial distribution.

These tables have the cumulative probabilities listed for n: P(X≤x₀)

Using the number of trials, the probability of success, and the expected value of X you can directly attain the corresponding cumulative probability without making any calculations.

>Since you are allowed to use the complement rule I'll show you how to calculate the probability using the formula:

P(X≥2) = 1 - P(X<2)= 1 - [P(X=0)+P(X=1)] ⇒

P(X=0)= \frac{10!}{(10-)0!0!} *0.2^{0} * 0.8^{10-0}= 0.1074

P(X=1)= \frac{10!}{(10-1)!1!} *0.2^{1} * 0.8^{10-1}= 0.2684

⇒ 1 - (0.1074+0.2684)= 0.6242

*-*

Using the table:

P(X≥2) = 1 - P(X<2)= 1 - P(X≤1)

You look in the corresponding table of n=10 p=0.2 for P(X≤1)= 0.3758

1 - P(X≤1)= 1 - 0.3758= 0.6242

*-*

Full text in attachment.

I hope it helps!

8 0
3 years ago
In the expression (x2 + 3), the base is
mixer [17]
<span>The base in the question you provided is the variable x,
hope this helps.
~BlurryFace</span>
5 0
3 years ago
Find the product. state your answer in standard form <br><br> (x+7)(x squared + 6x - 8)
USPshnik [31]

Answer:

{x}^{3}  +  13 {x}^{2}   + 34x  - 56

Step-by-step explanation:

(x + 7)( {x}^{2}  + 6x - 8) \\  = x ( {x}^{2}  + 6x - 8)  +  7( {x}^{2}  + 6x - 8)  \\  =  {x}^{3}  + 6 {x}^{2}  - 8x + 7 {x}^{2}  + 42x - 56 \\  = {x}^{3}  +  6 {x}^{2}  + 7 {x}^{2} + 42x - 8x - 56 \\  = {x}^{3}  +  13 {x}^{2}   + 34x  - 56 \\

6 0
3 years ago
Read 2 more answers
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