Answer:
The roots of the equation is real and repeated
Step-by-step explanation:
Here, we want to describe the nature of the roots of the given quadratic equation
To get the nature of the roots, we find the discriminant of the equation
The discriminant is;
b^2 - 4ac
In this case, b = -28 , a = 49 and c = 4
The discriminant is thus;
-28^2 - 4(49)(4)
= 784 - 784 = 0
Since the discriminant is zero, this means that the quadratic equation has real roots which are the same
(1) it can be both exterior of vertex or base. 180-130=50°
vertex is 50°: base=(180-50)/2=65°
base is 50°: vertex= 180-2*50=80°
vertex 50 base 65; vertex 80, base 50
(2)base=180-130=50°
vertex=180-2*50=80°
base 50 vertex 80
Answer:
23/12 or 1 and 11/12
Step-by-step explanation:
Your first step is that you need to gain a common denomitor. In this scenario, this is 12. To get this, you can either go through the given factors such as 3 having the factors of 6, 9, and 12 and 4 having the factors of 8, and 12.
Another method is the multiply the two given denominators together, but there are certain instances where you shouldn't do that.
Now that you have a common denominator, you need to change the numerators to accomadate the denominators. For 3 to turn into 12, you need to multiply it by 4, thus you have to do the same to the numerator. For 4 to turn into 12, you need to multiply it by 3. This will give you these two new fractions:
8/12 + 15/12
Add the numerators to get 23/12 and then simplify the two numbers to get the mixed number of 1 and 11/12.
Hope this helps!
