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n200080 [17]
3 years ago
11

What is the slope of the line that passes through the points (1, -6)(1,−6) and (-8, 9) ?(−8,9)?

Mathematics
1 answer:
Monica [59]3 years ago
4 0

Answer:

The answer to your question is  m = -5/3      

Step-by-step explanation:

Data

Point 1 = (1, -6)

Point 2 = (-8, 9)

Process

To find the slope just substitute the values in the formula and simplify.

Formula

slope = m = (y2 - y1) / (x2 - x1)

-Identify x1, y1, x2 and y2

  x1 = 1    y1 = -6   x2 = -8  y2 = 9

-Substitution

             m = (9 + 6) / (-8 - 1)

-Simplification

             m = 15/-9

-Result

             m = -5/3            

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p=1

Step-by-step explanation:

3p + 7 =  - 4(4 - 6p) + 2 \\ 3p + 7 =  - 16 + 24p + 2 \\ 3p - 24p =  - 16 + 2 - 7 \\  - 21p =  - 21

\frac{ - 21p}{ - 21}  =  \frac{ - 21}{ - 21}  \\ p = 1

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A recipe for cake needs ¾ of a cup of milk. You are making ½ of the recipe. How much milk do you need?
Bad White [126]
Multply across the fraction so
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Prove that sin^4x + cos^4x= sinxcosx
yKpoI14uk [10]

Answer:

(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)

Here we have the equation:

sin^4(x) + cos^4(x)

We can rewrite this as:

(sin^2(x))^2 + (cos^2(x))^2

Now we can add and subtract cos^2(x)*sin^2(x) to get:

(sin^2(x))^2 + (cos^2(x))^2 + 2*cos^2(x)*sin^2(x) - 2*cos^2(x)*sin^2(x)

We can complete squares to get:

(cos^2(x) + sin^2(x))^2 - 2*cos(x)^2*sin(x)^2

and we know that:

cos^2(x) + sin^2(x) = 1

then:

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This is the closest expression to what you wrote.

We also know that:

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If we replace that, we get:

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7 0
3 years ago
Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
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[(-7x - 8 - 8(x-1)) / (x-1)] / [(-7x - 8 + 7(x-1)) / (x-1)] = (-15x) / (-15) = x.

g(f(x)) = [-7*(x-8)/(x+7) - 8] / [(x-8)/(x+7) - 1] =

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5 0
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