Answer:
10 hours
Step-by-step explanation:
Given:
Average speed of submarine = 10 mph
Speed of carrier in the opposite direction = 20 mph
Distance between the submarine and carrier = 300 mi
To find:
The time taken so that the distance between them is 300 mi ?
Solution:
The relative speed when they are traveling in opposite direction = 10+20 = 30 mph
Formula:
So, the answer is <em>10 hours</em>.
Answer:
Number of student tickets were sold = 409
Step-by-step explanation:
Total number of tickets sold = 771
I.e Students ticket (S) + Non students ticket(N S) = 771
Total amount to be paid for tickets = $ 3037
Amount paid by students per tickets = $3
Amount paid by non-students per tickets = $5
So, according to question
S + NS = 771
3 S + 5 NS = 3037
Solve both equations
5 S + 5 NS = 771 × 5
3 S + 5 NS = 3037
so ,
(5 S + 5 NS) - (3 S + 5 NS ) = 3855 - 3037
Or, 2 S = 818
I.e S = = 409
Hence, The number of student tickets were sold = 409 Answer