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LiRa [457]
3 years ago
12

What's the 11th term 5,15,45,135

Mathematics
1 answer:
Tju [1.3M]3 years ago
6 0

Answer:

The 11th term is 295,245.

Step-by-step explanation:

We are given the sequence:

5, 15, 45, 135...

And we want to find the 11th term.

First, let's determine whether this is an arithmetic sequence or a geometric sequence.

Arithmetic sequences have common differences, while geometric sequences have common ratios.

We can determine that our sequence is a geometric sequence because each subsequent term is triple the previous term: our common ratio is 3.

To find the 11th term, we can write an explicit formula for our sequence. The explicit formula for a geometric sequence is given by:

x_n=ar^{n-1}

Where <em>a</em> is the initial term, <em>r</em> is the common ratio, and <em>n</em> is the <em>n</em>th term.

Since initial term is 5, and the common ratio is 3. Thus:

x_n=5(3)^{n-1}

To find the 11th term, substitute 11 for <em>n: </em>

<em />x_{11}=5(3)^{11-1}<em />

Evaluate. Thus, the 11th term is:

x_{11}=5(59049)=295245

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tiny-mole [99]

Answer:

x=3

Step-by-step explanation:

I am assuming that your equation is:

\sqrt{8x + 12}  + 4 = 10

Subtract 4 from both sides to get:

\sqrt{8x + 12}  = 6

Square both sides to get:

(\sqrt{8x + 12})^{2}  =  {6}^{2}

8x + 12 =3 6

8x =24

Divide both sides by 8 to get:

x =  \frac{24}{8}  = 3

6 0
4 years ago
If the cylinder above is similar to a second cylinder that has a radius of 10mm, what is the height of the second cylinder
julsineya [31]

Answer:

The height of the second cylinder is 30mm

Step-by-step explanation:

Given

Cylinder 1:

R = 15mm

H = 45mm

Cylinder 2

r = 10mm

See attachment

Required

Determine h, the height of the small one

To do this, we make use of the following equivalent ratios;

R : H = r : h

This gives:

15 : 45 = 10 : h

Express as fraction

\frac{15 }{ 45 }= \frac{10 }{ h}

Simplify

\frac{1 }{ 3}= \frac{10 }{ h}

Cross multiply

h *1 = 3 * 10

h = 30

8 0
3 years ago
5. A store owner has 12.58 kg of candy. If she puts the candy
Solnce55 [7]

Answer:

1.4 kg of candy

Step-by-step explanation:

Divide the amount of candy by the number of jars:

12.58/9

= approx. 1.4

So, each jar will have approximately 1.4 kg of candy

4 0
3 years ago
Given that the first step of the sequence of transformations that maps ABCD to PQRST is a reflection, identify the the transform
olga55 [171]

Answer:

d

Step-by-step explanation:

4 0
3 years ago
Solve the following quadratic equation by completing the square ✓3x^2 + 10x + 7✓3 = 0​
solmaris [256]

\sqrt{3}x^2+10x+7\sqrt{3}=0\\\\\sqrt3(x^2+\dfrac{10x}{\sqrt{3}}+7)=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+7=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+\dfrac{25}{3}-\dfrac{25}{3} +7=0\\\\(x+\dfrac{5}{\sqrt{3}})^2 = \dfrac{4}{3}\\\\|x+\dfrac{5}{\sqrt{3}}| = \dfrac{2}{\sqrt{3}}\\\\x_1 =   \dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = -\dfrac{3}{\sqrt{3}} = -\sqrt{3}\\\\x_2 =    -\dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = \dfrac{-7}{\sqrt{3}} = -\dfrac{-7\sqrt{3}}{3}

5 0
3 years ago
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