y = 8 -2x
x + 2 (8 - 2x) = 1
x + 16 - 4x = 1
x - 4x = -15
-3x = -15
x = 5
If x = 5, then we can substitute in...
5 + 2y = 1
2y = -4
y = -2
Now let us check that by substituting those values in to the equation
2x + y = 8
2 (5) + (-2) = 8
That is correct so we have the right values for x and y/
Answer:
10x^2 y(2x + 3y)
Step-by-step explanation:
20x^3 y + 30x^2 y^2.
Factor 10x^2y out of 20x^3y.
10x^2 y (2x) + 30x^2 y^2
Factor 10x^2y out of 30x^2y^2.
10x^2 y (2x) + 10x^2 y (3y)
Factor 10x^2y out of 10x^2 y (2x) + 10x^2 y (3y).
10x^2 y(2x + 3y)
you factor out 10x^2y from both side which you will then get 10x^2 y (2x) + 10x^2 y (3y) than you factor out 10x^2y again and get 10x^2 y(2x + 3y) your third option
A. X^2-10x. =-8
To complete the square you get half of -10 and then square that number half of -10 is -5 and -5 times -5 equals positive 25 that would you add to each side
x^2-10x+25=-8+25
17
