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3 years ago

Write the polynomial function of least degree with zeros 2 and 3 + i

Mathematics

1 answer:

OverLord2011 [107]3 years ago

6 0

Answer:

y= (x - 2)(x - (3 + i))(x + (3 + i))

I think this is the answer.

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= (1) - (179+6) (9+52i)-(1)

deff fn [24]

179+6=185

1-185= -184

9-1+52i= 8+52i

4 0

3 years ago

What is the kinetic energy of a bicycle that has a mass of 20 kg and is traveling at a velocity of 10 m/sec? KE= .5 x M x V^2

sleet_krkn [62]

You have the formula.
KE= 0.5(20 kg) (10 m/s)^2
KE= 10kg * 100 = 1000 J

8 0

3 years ago

7-4[3-(4y-5)] plz help me

ad-work [718]

Let's simplify step-by-step. 7−4(3−(4y−5))

Distribute: =7+(−4)(3)+(−4)(−4y)+(−4)(5)=7+−12+16y+−20

Combine Like Terms: =7+−12+16y+−20=(16y)+(7+−12+−20)=16y+−25

Answer: =16y−25

7 0

3 years ago

Read 2 more answers

What are the solutions of x^2-2x+5=0

sweet [91]

The solution of $x^{2}-2 x+5=0$ are 1 + 2i and 1 – 2i

Solution:

Given, equation is $x^{2}-2 x+5=0$

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ --- (1)

Let us determine the nature of roots:

Here in $x^{2}-2 x+5=0$ a = 1 ; b = -2 ; c = 5

$b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16$

Since $b^2 - 4ac < 0$ , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

$x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}$

On solving we get,

$x=\frac{2 \pm \sqrt{4-20}}{2}$

$x=\frac{2 \pm \sqrt{-16}}{2}$

$x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}$

we know that square root of -1 is "i" which is a complex number

$\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}$

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

6 0

3 years ago

Ruby misses 4% of the free throws she attempts in a season. How many total free throws did she attempt if she missed 46?

Phoenix [80]

Honestly I don’t even know what this is sorry I tried

5 0

3 years ago

Read 2 more answers