Repeating anyone ineed answers plsss?

the formula relates the time, t, in seconds for a pendulum with the length, l, in feet, to make one full swing back and forth. w

Dovator [93]

This shows that the length of a pendulum that makes one full swing in 2.2 seconds is 392.71 feet.

Given the formula for calculating the length of the pendulum expressed as:

$T= 2\pi\sqrt{\frac{L}{32} }$ where:

L is the length of the pendulum

T is the period of the pendulum

Given the following parameters:

Period T = 2.2 seconds

Substitute the given parameters into the formula will give;

$2.2=2\pi \sqrt{\frac{L}{32} }\\ (\frac{22}{6.58} )^2 =\frac{L}{32} \\L=3.5032 \times 32\\L = 3.92.71 feet$

So, this shows that the length of a pendulum that makes one full swing in 2.2 seconds is 392.71 feet.

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5 0

2 years ago

Electromagnetic radiation from a 8.25 mW laser is concentrated on a 1.23 mm2 area. Suppose a 1.12 nC static charge is in the bea

mylen [45]

Answer:

The maximum magnetic force is 2.637 x 10⁻¹² N

Explanation:

Given;

Power, P = 8.25 m W = 8.25 x 10⁻³ W

charge of the radiation, Q = 1.12 nC = 1.12 x 10⁻⁹ C

speed of the charge, v = 314 m/s

area of the conecntration, A = 1.23 mm² = 1.23 x 10⁻⁶ m²

The intensity of the radiation is calculated as;

$I = \frac{P}{A} \\\\I = \frac{8.25 \times 10^{-3} \ W}{1.23 \ \times 10^{-6} \ m^2} \\\\I = 6,707.32 \ W/m^2$

The maximum magnetic field is calculated using the following intensity formula;

$I = \frac{cB_0^2}{2\mu_0} \\\\B_0 = \sqrt{\frac{2\mu_0 I}{c} } \\\\where;\\\\c \ is \ speed \ of \ light\\\\\mu_0 \ is \ permeability \ of \ free \ space\\\\B_0 \ is \ the \ maximum \ magnetic \ field\\\\B_0 = \sqrt{\frac{2 \times 4\pi \times 10^{-7} \times 6,707.32 }{3\times 10^8} } \\\\B_0 = 7.497 \times 10^{-6} \ T$

The maximum magnetic force is calculated as;

F₀ = qvB₀

F₀ = (1.12 x 10⁻⁹) x (314) x (7.497 x 10⁻⁶)

F₀ = 2.637 x 10⁻¹² N

5 0

3 years ago

Which are the main regions of the periodic table? A. metals, nonmetals, gases B. solids, liquids, gases C. metals, semimetals, n

nlexa [21]

Answer:

the answer is C.

Explanation:

8 0

4 years ago

A beam of ultraviolet radiation, with frequency

andreyandreev [35.5K]

To develop this problem, we will apply Einstein's relationship which is in charge of the work done with the kinetic energy of the body versus the total energy of the system.

The energy can be calculated as

$E = hf$

Here,

h = Planck's Constant

f = Frequency

Our values are given as,

$f = 2.78*10^{15} Hz ,$

$W = 3.80 eV$

Therefore the Energy is

$E = hf$

$E = 6.625*10^{-34}J\cdot s(2.78*10^{15}Hz)$

$E = 1.84*10^{-18}J \rightarrow 1 J = 6.242*10^{18}eV$

Then,

$E = 11.48eV$

Applying the Einstein Relation we have that

$E = W+KE$

$KE = E -W$

$KE = 11.48eV-3.80 eV$

$KE = 7.68eV$

Therefore the maximum kinetic energy for an electron dislodged fromthe surface by the radiation is 7.68eV

6 0

3 years ago

A 16 lb block rests on a horizontal frictionless surface. A cord attached to the block, running horizontally, passes over a pull

quester [9]

Answer:

I = 6.2161900319309 slug-feet^2[/tex]

Explanation:

The moment of inertia of an object may simply be stated as a measure of how difficult it is to start it spinning, or to alter an object's spinning motion

The moment of inertia of an object is given by the expression

$I=mr^{2}$