A 50 kg bicyclist, traveling at a speed of 12 m/s, applies the brakes, slowing her speed to 3 m/s.
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The two possible angles obtained by using the qudratic equation are;
θ = 15.10° and θ2 = 73.51°
Given, speed of water = = 50ft/s
For the motion along x direction, time period can be calculated as follows:
35 = (50 × cosθ) t
t = 0.64 / cosθ
For the motion in y direction, an equation can be obtained as follows:
θ)
Plugging in the values we get:
θ)
-20 = -32tanθ - 10.304θ
Upon solving the above quadratic equation, we get,
tanθ = 0.27 , -3.38
Therefore,
tanθ = 0.27
θ = 15.10°
and, tanθ = -3.38
θ = 73.51
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