5.8x10^3
3.02x10^8
4.5x10^5
8.6x10^10
Left. Opposite of the direction the box is pushed.
Answer:
Geometrical optics, or ray optics, describes the propagation of light in terms of "rays" which travel in straight lines, and whose paths are governed by the laws of reflection and refraction at interfaces between different media.
Answer:
= 6.55cm
Explanation:
Given that,
distance = 1.26 m
distance between two fourth-order maxima = 53.6 cm
distance between central bright fringe and fourth order maxima
y = Y / 2
= 53.6cm / 2
= 26.8 cm
=0.268 m
tan θ = y / d
= 0.268 m / 1.26 m
= 0.2127
θ = 12°
4th maxima
d sinθ = 4λ
d / λ = 4 / sinθ
d / λ = 4 / sin 12°
d / λ = 19.239
for first (minimum)
d sinθ = λ / 2
sinθ = λ / 2d
= 1 / 2(19.239)
= 1 / 38.478
= 0.02599
θ = 1.489°
tan θ = y / d
y = d tan θ
= 1.26 tan 1.489°
= 0.03275
the total width of the central bright fringe
Y = 2y
= 2(0.03275)
= 0.0655m
= 6.55cm
To solve the problem it is necessary to apply the concepts related to the conservation of linear Moment, that is to say
Where,
m = Mass
v = Velocity
P = Linear momentum
For the given data we have to:
The components of this force would be given by,
According to the definition given at the end of the problem, this component corresponds to that expressed for x and y.
Applying the previous equation we have,
<em>Note: The component at this direction must also decomposed</em>
The mass is 143g=0.143kg, then:
Therefore the final vector is:
