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3 years ago

At office Depot, Suzy bought

Mathematics

1 answer:

pashok25 [27]3 years ago

5 0

Answer:

$1.64

Step-by-step explanation:

27.95 x 0.055 = $1.64

If you wanted to find the final price of the filing cabinet WITH sales tax:

27.95 + 1.64 = $29.59

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Part B The mass of an average grain of rock salt is about 40 times the mass of an average grain of table salt. If you multiply t

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Answer: Its (A)

Step-by-step explanation:

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3 years ago

An equation is shown below: 5(2x-8) +15 = -15 write the steps you will use to solve the equation and explain each step

faust18 [17]

Answer:

5(2x-8)+15=-15

10x-40+15=-15

10x-25=-15

+25 +25 (add 25 to both sides)

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10x=10

divide by 10 on both sides

x=1

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3 years ago

Read 2 more answers

Find the slope and the y-intercept of the line. 4x-5y=5

Evgen [1.6K]

Answer:

Step-by-step explanation:

4x - 5y= 5

-4x. -4x

-5y = -4x + 5

divide all by -5

y= 4/5x -1

slope is 4/5

y intercept is -1

4 0

3 years ago

Express as a trinomial.<br> (3x + 7)(3x + 4)

timama [110]

Answer:

9x² + 33x + 28

Step-by-step explanation:

$(3x + 7)(3x + 4)\\= 3x(3x + 4) + 7(3x + 4)\\= 9x^2 + 12x + 21x + 28\\= 9x^2 + 33x + 28$

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3 years ago

A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

$S=2\pi rh$

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

Thus, the surface area of the cylinder,

$S=2\pi r(\sqrt{16-4r^2})$

Differentiating with respect to r,

$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

$=2\pi (\sqrt{2})(\sqrt{8})$

$=2\pi \sqrt{16}$

$=8\pi\text{ square cm}$

4 0

3 years ago