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1 year ago

Match the Algebraic expressions with the type of transformation.

Mathematics

1 answer:

shtirl [24]1 year ago

6 0

Answer:

2 no.reflection

6 no diliation

8 no reflection

7 no rotation

5 no rotation

3 no rotation

4 no translation

9 no translation

Step-by-step explanation:

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Hurry please!!! Fast response

AlladinOne [14]

Answer:

$SA= \frac{2}{3} \pi rl+16 \pi r^2$

Step-by-step explanation:

Surface area of the original cone

$SA= \pi r l + \pi r^2... (1)$

When, radius is quadrupled and slant height is reduced to one sixth

$i. e. \: \:r = 4r\: \: \&\:\: l= \frac{1}{6}l$

Plug the above values of r and $l$ in equation (1), new surface area becomes:

$SA= \pi (4r)\times \frac{1}{6} l+ \pi (4r)^2$

$SA= \frac{4}{6} \pi rl+16 \pi r^2$

$\huge \purple {\boxed {SA= \frac{2}{3} \pi rl+16 \pi r^2}}$

8 0

2 years ago

Am I correct <br> 2017 -1846= 171<br> 2017-1781= 236<br> 1847-1781=65 yrs difference

Anit [1.1K]

Yes for the first one, yes for the second one, and yes for the third one although your subtraction equation had the wrong year (its not 1847 its 1846) but the answer was right, 65.

5 0

2 years ago

The areas of two similar octagons are 9 m² and 25 m². What is the scale factor of their side lengths? PLZ HELP PLZ PLZ PLZ

torisob [31]

Answer:

$\frac{3}{5}$

Step-by-step explanation:

Let the side length for the octagon having 9m² as area = x

Side length for the octagon having area of 25m² = y.

Thus:

$\frac{9}{25} = (\frac{x}{y})^2$ (area of similar polygons theorem)

The scale factor of their sides would be $\frac{x}{y}$ . Which is:

$\sqrt{\frac{9}{25}} = \frac{x}{y}$

$\frac{\sqrt{9}}{\sqrt{25}} = \frac{x}{y}$

$\frac{3}{5} = \frac{x}{y}$

Scale factor of their sides = $\frac{3}{5}$

6 0

2 years ago

HELP ILL GIVE BRAINLIEST PLEASE I NEED TO PASS MY TEST

Naily [24]

<h2>You need a reflection across the y-axis!</h2>

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2 years ago

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s2008m [1.1K]

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