Question

A 13.5 liter balloon is heated from 248k to 324k. what will it's new volume be?​

Answer 1

Answer:

The new volume is approximately 17.637 liters

Explanation:

The given parameters in the question are;

The initial volume of the gas, V₁ = 13.5 Liter

The initial temperature of the gas, T₁ = 248 K

The new temperature of the gas, T₂ = 324 K

A balloon containing gas that experiences an increase in the temperature of the gas content under constant pressure obeys Charles law which states that the volume of a given mass of gas is directly proportional to its Kelvin temperature is expressed mathematically as follows;

$\dfrac{V_1}{T_1} = \dfrac{V_2}{T_2}$

Where;

V₁ = The initial volume of the gas

T₁ = The initial temperature of the gas

V₂ = The new volume of the gas

T₂ = The new temperature of the gas

From the question, we have;

V₁ = 13.5 Liter

T₁ = 248 K

T₂ = 324 K

Therefore, we have;

${V_2}= \dfrac{V_1}{T_1} \times T_2$

${V_2}= \dfrac{324 \ K}{248 \ K} \times 13.5 \ L=17\dfrac{79}{124} \ L\approx 17.637 \ L$

The new volume, V₂ ≈ 17.637 L.