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3 years ago

The compound 1-Butene is modeled here.

Chemistry

1 answer:

Grace [21]3 years ago

6 0

Answer:

Option-A. Covalent bonds would need to form between the molecules.

Explanation:

In given statement the molecules of 1-Butene are adding to each other forming a macromolecule called as Polybutene. Such type of reactions are called Polymerization reactions.

Polymerization reactions are those reactions in which small molecules called as monomers join together to form a large molecule also known as polymers. These reactions are done via different mechanisms like addition reaction, condensation reactions e.t.c.

Example:

Polybutene (polymer) is made up of 1-butene (monomers) through addition reaction in which the double bonds of 1-butene molecules are involved in the formation of new single covalent bond via acid catalyzed, base catalyzed or free radical mechanisms.

n H₂C=CH-CH₂-CH₃ → --[H₂C-CH(C₂H₅)]-n--

In above equation "n" represent large number, H₂C=CH-CH₂-CH₃ represent 1-Butene (monomer) and --[H₂C-CH(C₂H₅)]-n-- represent polybutene (polymer).

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Answer:

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Explanation:

there are atoms of different elements is sodium atom

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3 years ago

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ASHA 777 [7]

Answer: The moles of melatonin are 0.000043

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

Given mass of melatonin = 0.01 g

Molar mass of melatonin $(C_{13}H_{16}N_2O_2)$ = 232.28 g/mol

$\text{Number of moles of melatonin}=\frac{0.01 g}{232.28g/mol}=0.000043mol$

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3 years ago

odium carbonate (Na2CO3Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be add

Arte-miy333 [17]

Answer : The mass of sodium carbonate added to neutralize must be, $6.54\times 10^3kg$

Explanation :

First we have to calculate the moles of $H_2SO_4$ .

$\text{Moles of }H_2SO_4=\frac{\text{Mass of }H_2SO_4}{\text{Molar mass of }H_2SO_4}$

Given:

Molar mass of $H_2SO_4$ = 98 g/mole

Mass of $H_2SO_4$ = $6.05\times 10^3kg=6.05\times 10^6g$

Conversion used : (1 kg = 1000 g)

Now put all the given values in the above expression, we get:

$\text{Moles of }H_2SO_4=\frac{6.05\times 10^6g}{98g/mol}=6.17\times 10^4mol$

The moles of $H_2SO_4$ is, $6.17\times 10^4mol$

Now we have to calculate the moles of $Na_2CO_3$

The balanced neutralization reaction is:

$Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+H_2CO_3$

From the balanced chemical reaction we conclude that,

As, 1 mole of $H_2SO_4$ neutralizes 1 mole of $Na_2CO_3$

So, $6.17\times 10^4mol$ of $H_2SO_4$ neutralizes

Now we have to calculate the mass of $Na_2CO_3$

$\text{ Mass of }Na_2CO_3=\text{ Moles of }Na_2CO_3\times \text{ Molar mass of }Na_2CO_3$

Molar mass of $Na_2CO_3$ = 106 g/mole

$\text{ Mass of }Na_2CO_3=(6.17\times 10^4mol)\times (106g/mole)=6.54\times 10^6g=6.54\times 10^3kg$

Thus, the mass of sodium carbonate added to neutralize must be, $6.54\times 10^3kg$

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4 years ago

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Leto [7]

Question: What do you need help with?

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3 years ago

The work function is the energy that must be supplied to cause the release of an electron from a photoelectric material. The cor

vladimir2022 [97]

Answer:

No photoelectric effect is observed for Mercury.

Explanation:

From E= hf

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f= frequency of incident light

Threshold Frequency of mercury= 435×10^3/ 6.6×10^-34 × 6.02×10^23

f= 11×10^14 Hz

The highest frequency of visible light is 7.5×10^14. This is clearly less than the threshold frequency of mercury hence no electron is emitted from the mercury surface

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4 years ago