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3 years ago

Plz help!!!!!!!!!!!!!!! 100 points! any links or wrong answers will be flaged

Mathematics

1 answer:

garik1379 [7]3 years ago

7 0

Answer:

Part A: 431070.9 ergs

Part B: 1.6 x 103mm

Step-by-step explanation

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Sally has 3 /4 of a yard of ribbon. she uses 1/8 yard of ribbon to make each bow. does she have enough ribbon to make 7 bows?

tekilochka [14]

Answer:

Step-by-step explanation:

3/4 of a yard is equal to 6/8 of a yard. If Sally wants 7 ribbons, she needs at least 7/8 yards of ribbon.

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3 years ago

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What number am i missing please only tell me the one missing!!!

makvit [3.9K]

Answer:

Step-by-step explanation:

40 can be multiplied by 5, 8 times. 8 multiplied by 2 is 16.

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3 years ago

Find the h.c.f of

yuradex [85]

The greatest common factor will be (x² – xy + y²).

<h3>Greatest common factor</h3>

This is a value or expression that can divide the given expressions without leaving a remainder.

Given the following expressions

x^3+^3 and x^2 - xy + y^2

Expand x^3+y^3

x^3+y^3 =(x + y)(x² – xy + y²).

Since (x² – xy + y²) is common to both expression, hence the greatest common factor will be (x² – xy + y²).

Learn more on GCF here: brainly.com/question/902408

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2 years ago

How do I find the area of this shape

vazorg [7]

There's two ways, you can either multiply 11 and 7 to get 77 and then divide by 2, OR, you can divide 11 by 2 and get 5.5 and multiply that by 7, hope this makes sense, if you don't understand just comment and I'll explain it more :)

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3 years ago

A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago