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aliina [53]
3 years ago
14

Someone that knows physics and can explain please help.

Physics
1 answer:
disa [49]3 years ago
6 0

Answer:

500uF

Explanation:

On the graph C (Charge/Coulomb) increases by .005 each measurement and the Voltage by 10. Capacitance= Charge/Potential difference. .005/10 =.0005 which is written as 500uF. This works since if u simply work it backwards, 1uF is 1 millionth of a Coulomb times that by 500 which gives .0005 then by 10 for Voltage and then u get the original charge.

So the answer is 500uF.

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Угол между осями поляризатора и
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Nolur acil lütfen yalvarırım yalvarırım
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A triangle ∆P QR has vertices P(3, 2, −4), Q(1, 0, −4), R(2, 1, 1). Use the distance formula to decide which one of the followin
777dan777 [17]

Answer:

a. FALSE

b.TRUE

C. FALSE

Explanation:

The formula fot the distance between two points is given as

d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} +(z_{2}-z_{1})^{2}}\\

hence we determine the distances between all the points

a.P(3,2,-4), Q(1,0,-4), R(2,1,1)

PQ=\sqrt{(1-3)^{2} +(0-2)^{2} +(-4-(-4))^{2}}\\PQ=\sqrt{4+4+0}\\ PQ=\sqrt{8}

For point PR

we have

PR=\sqrt{(2-3)^{2} +(1-2)^{2} +(1-(-4))^{2}}\\PR=\sqrt{1+1+9}\\ PR=\sqrt{11}\\

|PQ|\neq |PR|

B. For point RP

RP=\sqrt{(3-2)^{2} +(2-1)^{2} +(-4-1)^{2}}\\RP=\sqrt{1+1+25}\\ RP=\sqrt{27}

for point RQ  we have

RQ=\sqrt{(1-2)^{2} +(0-1)^{2} +(-4-1)^{2}}\\RQ=\sqrt{1+1+25}\\ RQ=\sqrt{27}

|RP|=|R Q|

C.

QP=\sqrt{(3-1)^{2} +(2-0)^{2} +(-4+4)^{2}}\\QP=\sqrt{4+4+0}\\ QP=\sqrt{8}

For point Q R

QR=\sqrt{(2-1)^{2} +(1-0)^{2} +(1-(-4))^{2}}\\QR=\sqrt{1+1+9}\\ QR=\sqrt{11}\\

QP\neq QR

6 0
3 years ago
PLS HELP !!
Ira Lisetskai [31]
A because it’s basic kinetic example
4 0
3 years ago
Read 2 more answers
How many joules of heat are needed to raise the temperature of 50.0 g of aluminum from 10°C to 110°C, if the specific heat of al
dusya [7]

Answer:

Heat required to raise the temperature of the aluminium is 4750 J

Explanation:

As we know that the heat energy required to raise the temperature of the aluminium is given as

Q = ms\Delta T

here we know that

m = 50 g

\Delta T = 110 - 10

\Delta T = 100 ^oC

so we have

Q = 50(0.95)(100)

Q = 4750 J

5 0
4 years ago
A 20.0 kg suitcase is raised 3.0 m above a platform. How much work is done on the suitcase?
Lisa [10]

Answer:

600

Explanation:

m=20

g=10m\s2

h=3m

we have

w=m*g*h

=20*10*3

=600joule

3 0
4 years ago
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