Answer:
D The chemicals on the right side of a chamical equation
The value of the thrust developed by the engine of a boeing 777 in N and Kgf are ;
i) 376616N
ii) 38430Kgf
<h3>What is force?</h3>
Force is a push or a pull. The reactive force always serve to balance the applied force. We are here asked to convert the the thrust developed by the engine of a boeing 777 which is about 85400 lbf to the following units;
i) N
ii)kgf
Thus;
1 Ib = 0.45 Kg
1 lbf = 0.45 Kg * 9.8 m/s^2 = 4.41 N
We know that;
1 lbf = 4.41 N
85400 lbf = 85400 lbf. * 4.41 N/1 lbf
= 376616N
Again;
1 lbf = 0.45 Kgf
85400 lbf = 85400 lbf * 0.45 Kgf/1 lbf
= 38430Kgf
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Answer:
0.06
Explanation:
On a level surface, normal force = weight.
Sum of the forces in the x direction:
∑F = ma
Nμ = ma
mgμ = ma
gμ = a
μ = a/g
μ = (0.6 m/s²) / (9.8 m/s²)
μ = 0.06
The formula is M=Fd
so we have F=84N and d=0.25m
Now we just replace F and d into the formula M=84N×0.25m
And the last thing we do is calculate it
M=21Nm
7000w + 1637kw =8637kw+25.0m=loud sound