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tia_tia [17]
3 years ago
9

how long will it take a car to go from a complete stop to 44 km/h if they are accelerating at 5 kilometers per hour squared

Physics
1 answer:
PIT_PIT [208]3 years ago
8 0
44/5 seconds to g<span>o from a complete stop to 44 km/h</span>
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A car travels along a straight road at a steady 40 MPH.Are the forces on the car balanced or unbalanced? Explain.
Nutka1998 [239]
They are balanced b/c the motion is constant
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3 years ago
Why is it generally easy to filter out particles in suspension?
sattari [20]

Answer: A suspension is a heterogeneous mixture in which some of the particles settle out of the mixture upon standing. The particles in a suspension are far larger than those of a solution, so gravity is able to pull them down out of the dispersion medium (water).

Explanation:

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2 years ago
A current of 2.0 A flows through a circuit containing a motor with a resistance of 12 ohm how much energy is converted if the mo
bearhunter [10]

The energy converted is 48 Joules

<h3>How to determine the energy</h3>

We have the formula for energy in a circuit as

Energy = Power × time

Power = I^2 R

Current, I = 2.0 A

time = 1 minute

Resistance = 12 Ohm

Substitute into the formula

Power = 2 × 2 × 12

Power = 48 Watts

Energy = 48 × 1

Energy = 48 Joules

Thus, the energy converted is 48 Joules

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brainly.com/question/14950715

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5 0
1 year ago
Lucy took 3 hours to cover 2/3 of a journey. She covered the
Grace [21]

Deleted this answer, sorry for any inconveniences that it may have caused.

7 0
3 years ago
Parker (73.2 kg) is being dragged down the hall with an applied force of 123 N. If the frictional force is 27.4 N, what is the c
levacccp [35]

Answer:

The coefficient of friction in the hall is 0.038

Explanation:

Given;

mass of the Parker, m = 73.2 kg

applied force on the parker, F = 123 N

frictional force, Fs = 27.4 N

the coefficient of friction in the hall = ?

frictional force is given by;

Fs = μN

Where;

μ is the coefficient of friction

N is normal reaction = mg

Fs = μmg

μ = Fs / mg

μ = (27.4) / (73.2 x 9.8)

μ = 0.038

Therefore, the coefficient of friction in the hall is 0.038

6 0
3 years ago
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