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2 years ago

Could somebody help me with that, please?

Mathematics

1 answer:

True [87]2 years ago

5 0

Answer:

Line JP, and Line PK

angle <K and angle<M

Step-by-step explanation:

In geometry congruent is defined as the following:

- Two figures or objects that are of the same shape and size

Knowing this, you also need to define another term in the question: "segments"

a.k.a - a portion cut off from a geometric figure by one or more points, lines, etc.

Therefore you need to be looking at lines that are similar to each other within the problem.

If you look at the image only two lines are similar to each other, as signified by the singular dash line through each side:

Line JP, and Line PK

If that doesn't work that would mean it is signifiying the angles which would be angle <K and angle<M.

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The speed of the boat going with a current is 20 mph. When the boat goes against the current, the speed is 16 mph. Find the spee

adoni [48]

Answer:

The speed of the boat in still water is 18 mph.

The speed of the current is 2 mph

Step-by-step explanation:

Let x represent the speed of the boat in still water.

Let y represent the speed of the current.

When the boat goes against the current, the speed is 16 mph. Assuming it traveled against the current while going upstream, its total speed would be (x - y) mph. It means that

x - y = 16 (equation 1)

Going downstream, the boat averages 20 mph. Assuming it traveled with the current, its total speed would be (x + y) mph. It means that

x + y = 20 (equation 2)

Adding both equations, it becomes

2x = 36

x = 36/2

x = 18 mph

Substituting x = 18 into equation 1, it becomes

18 - y = 16

y = 18 - 16

y = 2 mph

4 0

3 years ago

The entire rectangle below has an area of .

Nastasia [14]

Answer:

Hence the required ans. Is 24cm2.

Step-by-step explanation:

I have explained Ans. at above. See it and how you Understand it. If you have any doubt then Comment . if you Like then Plz Give me 5 star rating

5 0

3 years ago

25 Points ! Write a paragraph proof.<br> Given: ∠T and ∠V are right angles.<br> Prove: ∆TUW ∆VWU

vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and

including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ

≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

leg of the 2nd right angle Δ

* Lets solve the problem

- There are two triangles TUW and VWU

- ∠T and ∠V are right angles

- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

other and one common side, so we can use the case AAS

- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

7 0

3 years ago

Read 2 more answers

Geometry math question no Guessing and Please show work

MAXImum [283]

If the point P(x, y) partitions the segment AB in the ratio 1 : 1, then the point P is midpoint of segment AB.

The formula of a midpoint of segment:

$A(x_A;\ y_A),\ B(x_B,\ y_B)\\\\P_{AB}\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)$

We have:

$A(13,\ 1)\to x_A=13,\ y_A=1\\B(-5,\ -3)\to x_B=-5,\ y_B-3\\\\P\left(\dfrac{13+(-5)}{2};\ \dfrac{1+(-3)}{2}\right)\to P\left(\dfrac{8}{2};\ \dfrac{-2}{2}\right)\to P(4,\ -1)$

Answer: C. (4, -1)

3 0

3 years ago

Plz help will mark brainliest

Kryger [21]

∆ABC=∆DEF

AB=DE –>String

BC=EF–> Rib

m<C=m<F=90° –>List

AC=DF

So m<A=m<D=35 (It is not clear whether the number is 35 or 36, but the same number)

8 0

2 years ago