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vagabundo [1.1K]
3 years ago
9

I don't know how to do this

Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0
He could have 30 dimes and 13 quartars
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If f(x) = (4x-3)^2, then f(-2)=?<br> A: -121<br> B: -22<br> C: 22<br> D: 25<br> E: 121
SOVA2 [1]
The answer is E. 121.
7 0
3 years ago
R Problem Old Faithful is a geyser located in Yellowstone Nation Park in Wyoming. It received the name "Old Faithful" by the Was
Tpy6a [65]

Answer:

Step-by-step explanation:

The first 6 rows of the eruptions data :

eruptions waiting

1 3.600 79

2 1.800 54

3 3.333 74

4 2.283 62

5 4.533 85

6 2.883 55

R code :

1. You can directly access the "Faithful" data in R without importing the data. The dataset faithful is present in the R or you can load the datasets. or use install the datasets.load. package

If you have the data in a text file, make sure all the columns and rows are separated by commas

Step 1: open notepad

Step 2: enter data with no spaces but only commas

Step 3: save the file as ‘faithful.txt’ on your Desktop

# Get R help

?read.table

# Import the data

rain<-read.table("C:/Users/YOUR-NAME/Desktop/faithful.txt", header = TRUE,

                  sep = ",")

Check the data

data("faithful") #Loading Faithful data

head(faithful, 6) #Reading first 6 rows of the data

8 0
3 years ago
Solve each system of equations algebraically. For each one, explain what the solution (or lack thereof) tells you
Paul [167]

Answer:

a: no solutions

b: (2, 3)

Step-by-step explanation:

a:

In both equations, the slope of x is the same, but the y-intercept is not, which means they are parallel. Therefore, this system of equations has no solutions.

b:

Since both of the equations are equal to y, we can set them equal to each other:

\frac{1}{2}x^2+1= 2x-1\\x^2 + 2 = 4x - 2\\x^2-4x+4=0

We can solve by factoring (by finding a number that multiplies to 4 and adds up to -4):

(x-2)^2 = 0

x = 2

Now, to find y, plug-in x to any of the equations:

y = 2*2-1 = 3

Therefore, the solution to this system of equation is (2, 3)

I hope this helped.

4 0
3 years ago
imagine reporting a question like if you dont like it just go to anothr question like yall be pressed for what.... love yall tho
mario62 [17]

Answer:

what the heck

was that also i'm country

Step-by-step explanation:

4 0
3 years ago
Niobium-91 has a half-life of 680 years. After 2,040 years, how much niobium-91 will remain from a 300. 0-g sample? 3 g 18. 75 g
alekssr [168]

Answer:

Amount of Niobium-91 initially

= 300/91 =3.2967mol

2040 years = 3 ×680 = 3 half-lives

therefore, amount left = 0.4121mol

mass of Niobium-91 remaining = 0.4121 ×91 =37.5g

Please give brainliest

8 0
2 years ago
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