Answer:
125/6(In(x-25)) - 5/6(In(x+5))+C
Step-by-step explanation:
∫x2/x1−20x2−125dx
Should be
∫x²/(x²−20x−125)dx
First of all let's factorize the denominator.
x²−20x−125= x²+5x-25x-125
x²−20x−125= x(x+5) -25(x+5)
x²−20x−125= (x-25)(x+5)
∫x²/(x²−20x−125)dx= ∫x²/((x-25)(x+5))dx
x²/(x²−20x−125) =x²/((x-25)(x+5))
x²/((x-25)(x+5))= a/(x-25) +b/(x+5)
x²/= a(x+5) + b(x-25)
Let x=25
625 = a30
a= 625/30
a= 125/6
Let x= -5
25 = -30b
b= 25/-30
b= -5/6
x²/((x-25)(x+5))= 125/6(x-25) -5/6(x+5)
∫x²/(x²−20x−125)dx
=∫125/6(x-25) -∫5/6(x+5) Dx
= 125/6(In(x-25)) - 5/6(In(x+5))+C
Answer:
Number of Adults Ticket=393
Number Of Students Tickets=792
Step-by-step explanation:
Let 'x' be the Adult's tickets
Let 'y' be the Student's tickets
x+y=1185 (total sold tickets)
5x+y=2757(total cost of tickets)
-(5x+y=2757)x+y=1185
(-5x-y)- x+y=1185-2757
=-4x+0 = (-1572)
=-4x=(-1572)
x= (-1572)÷-4
=393
=x+y=1185
=393+y=1185
=y=792
So Number of Adults Ticket=393
Number Of Students Tickets=792
Hope it Help
F(x) = 4 [cos (x)]^2 - 3 = 0
4[cos(x)]^2 = 3
cos(x) = √3 / 2
That happens in the first and fourth quadrants, for the angles 30 degrees and 330 degrees.
Answer: x = 30 degrees and x = 330 degrees
The volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)
<h3>How to determine the volume?</h3>
The complete question is added as an attachment
From the attached image, we have:
Length = 12 - 2x
Width = 7 - 2x
Height = x
The volume is calculated as:
Volume = Length * Width * Height
Substitute the known values in the above equation
Volume = (12 - 2x) * (7 - 2x) * x
This gives
Volume = x(12 - 2x)(7 - 2x)
Hence, the volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)
Read more about polynomial at:
brainly.com/question/4142886
#SPJ1
This can be solved using a system of equations.
Subtract y from both sides.
Substitute:
Subtract 80 from both sides:
Divide both sides by 5:
Substitute.
