Yes...? I think so. I might not be right
The period of the function is that distance where the function becomes equal again.
We have then:
Part 1:
The period of the function is:
T = 3
Part 2:
The period of the function is:
T = 4
Answer:
The period of functions 1 and 2 respectively are:
T = 3
T = 4
Answer:

General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Property [Multiplied Constant]: ![\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29)
Derivative Property [Addition/Subtraction]:
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Differentiate</u>
- Derivative Property [Addition/Subtraction]:
![\displaystyle y' = \frac{d}{dx}[x^2] - \frac{d}{dx}[3]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bx%5E2%5D%20-%20%5Cfrac%7Bd%7D%7Bdx%7D%5B3%5D)
- Basic Power Rule:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
I have no idea what options but technically it’s possible to stack it an infinite amount of ways, TECHNICALLY, I’m not sure if it’s the answer you are looking for though good luck