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Charra [1.4K]
3 years ago
10

Please help !! find the volume

Mathematics
1 answer:
RoseWind [281]3 years ago
6 0
It’s 102in sorry if I’m late to answer
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x=-2

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\frac{1}{6{x}^{2} }  =  \frac{1}{2x}  + \frac{7}{6 {x}^{2} }  \\  \frac{7}{6 {x}^{2} }  -  \frac{1}{6{x}^{2} }  +  \frac{1}{2 {x} }  = 0  \:  \:  \: \:  \:  ( -  \frac{1}{6 {x}^{2} } \: throughout) \\  \frac{6}{6 {x}^{2} }  +  \frac{1}{2x}  = 0  \:  \:  \:  \:  \: (simplify)\\ \frac{1}{ {x}^{2} }  +  \frac{1}{2x}  = 0 \\   \frac{2 {x}^{2} }{ {x}^{2} } +  \frac{2 {x}^{2} }{2x}  = 0 \:  \:  \:  \:  \: ( \times 2 {x}^{2} \:  throughout) \\ 2 + x = 0  \:  \:  \:  \:  \: (simplify)\\ x =  - 2

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3 years ago
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