11 L because you just need to use a pie chart
Hello!
The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa
To solve that we need to apply
Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:
![P2= \frac{P1}{T1}*T2= \frac{103 kPa}{25}*928=3823,36 kPa](https://tex.z-dn.net/?f=P2%3D%20%5Cfrac%7BP1%7D%7BT1%7D%2AT2%3D%20%5Cfrac%7B103%20kPa%7D%7B25%7D%2A928%3D3823%2C36%20kPa)
Have a nice day!
Answer:
According to Boyle's law pressure of a particular amount of gas is inversely proportional to the volume of the gas. So, when we increase the pressure of the gas the volume of the gas decrease and the gas start to condense.
Explanation:
Answer:
33.63 g H₂O
Explanation:
The mole ratio of HNO₃ and H₂O is 6 : 2
Hence, 16.9 moles of HNO₃ will produce = 2/6×5.6 = 1.86 moles of H₂O
Also,
Mass = Moles × M.Mass
Mass = 1.86 mol × 18.02 g/mol
Mass = 33.63 g H₂O
Answer:
the answer is C4H10 I hope I helped