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OleMash [197]
3 years ago
8

What ph measurements of rainwater would indicate acid precipitation?

Chemistry
1 answer:
CaHeK987 [17]3 years ago
8 0
The answer is ph 4.1
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If the crucible originally weighs 3.715 g and 2. 000 g of hydrate are added to it , what is the weight of the water that is lost
dimulka [17.4K]
For this, you need to know 1) the mass of the hydrate and 2) the mass of the anhydrous salt. Once you have both of these, you will subtract 1) from 2) to find the mass of the water lost.

From the problem, you know that 1) = 2.000 g.

Now you need to find 2). You know that your crucible+anhydrous salt is 5.022 g. To find just the anhydrous salt, subtract the mass of the crucible (3.715 g).

1) = 5.022 g - 3.715 g = 1.307 g

Now you can complete our original task.

Mass H2O = 2) - 1) = 2.000 g - 1.307 g = 0.693 g.


4 0
4 years ago
4. Nowadays, clinical thermometer is replaced by digital thermometer,why?<br>​
White raven [17]

Answer:

<h2>Digital thermometer are used these days instead of clinical thermometers because: Digital thermometers are designed to be more accurate. Most digital thermometers have digital screening which extract temperature of wherever you are measuring. </h2>
4 0
3 years ago
true or false: for genetic engineering the specific traits of a given organism are located on the DNA sequence of the chromosome
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True, moving genes from a chromosome of one organism to a chromosome of a different organism.
4 0
3 years ago
How many grams are in 0.21mol sample of ethyl alcohol?
vampirchik [111]
Mass = moles x molar mass
Molar mass of eythl alcohol = 46

Mass= 0.21 x 46= 9.66g
7 0
4 years ago
QUESTION 18
Levart [38]

Answer:

-43.3 °C

Explanation:

To find the temperature, you need to use the Ideal Gas Law equation. The equation looks like this:

PV = nRT

In this formula,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Law constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

By plugging the given values into the equation and simplifying, you can find the temperature. After you get a temperature, you need to convert it into Celsius.

P = 2.88 atm                              R = 0.08206 atm*L/mol*K

V = 3.76 L                                   T = ? K

n = 0.574 moles

PV = nRT

(2.88 atm)(3.76 L) = (0.574 moles)(0.08206 atm*L/mol*K)T

10.8288 = (0.04710244)T

230. K = T

Kelvin - 273.15 = Celsius

230 K - 273.15 = -43.3 °C

8 0
2 years ago
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