1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Finger [1]
8 months ago
9

most radioactive atoms “spontaneously” decay to a more stable form. where does the “additional” energy go once the atoms have de

cayed to a more stable form?
Chemistry
1 answer:
blsea [12.9K]8 months ago
4 0

When most radioactive atoms “spontaneously” decay to a more stable form the “additional” energy is converted to radiation with the emission of radioactive particles.

<h3>What is radioactivity?</h3>

Radioactivity is the spontaneous decay of the nucleus of an atom with the emission of radiation and nuclear particles.

Elements that spontaneously decay are called radioactive elements.

When these radioactive elements decay, they form more stable isotopes or elements.

The spontaneous decay of atoms of radioactive elements is in order for the nucleus of the atom to become stable and non-radioactive.

Learn more about radioactivity at:

brainly.com/question/26626062

#SPJ1

You might be interested in
What is the pressure of 1.20 moles of SO2 gas in a 4L container at 30 degrees celsius
geniusboy [140]
Let suppose the Gas is acting Ideally, Then According to Ideal Gas Equation,

                                       P V  =  n R T
Solving for P,
                                       P  =  n R T / V     ----- (1)
Data Given;

Moles  = n = 1.20 mol

Volume  = V =  4 L

Temperature  = T = 30 + 273 = 303 K

Gas Constant  = R = 0.08206 atm.L.mol⁻¹.K⁻¹

Putting Values in Eq.1,

                     P  =  (1.20 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 303 K) ÷ 4 L

                     P  =  7.45 atm
6 0
3 years ago
Read 2 more answers
According to bohr's model of the atom in which orbitals do electrons have the least energy
sasho [114]
According to Bohr's model of the atom, the higher the orbital in which the electrons are found, the higher their energy or excitation state. Therefore, the electrons with the least amount of energy are those at the lowest orbitals, which are closer to the nucleus. 
These orbitals are characterized by 4 quantum numbers, namely the principal quantum number (n), orbital angular momentum quantum number (l), the magnetic quantum number (ml), and the electron spin quantum number (ms). The principal quantum number reflects the distance of the electrons from the nucleus with n=1 as the orbital closest to the nucleus. Thus, according to Bohr's model, electrons in the orbital with n=1 have the lowest energy. 
7 0
3 years ago
A 200. 0-ng sample of sodium-24 was stored in a lead-lined cabinet for 45 hours. The half-life of sodium-24 is 15 hours. How muc
ipn [44]

Answer:

25 gm would be left

Explanation:

45 hours is 3 half lives

200 gm  * 1/2 * 1/2 * 1/2 = 25 gm

3 0
1 year ago
Convert the following to grams, <br> a. 0.100 moles of CO2
Svetlanka [38]
.100 mol CO2 x \frac{44.01 g}{1 mol}
using the values of the periodic you first add the masses of C (12.01g) and O (there are two so it'll be 32.00g). That value will give the mass of 1mole of CO2.


I hate to do this, but
https://youtu.be/Pft2CASl0M0 is a link to a mr andersen video. I dislike watching these cause this is what my teacher uses instead of actually having to teach herself.
3 0
2 years ago
Electric power is measured in watts (1 W = 1 J/s). About 95% of the power output of an incandescent bulb is converted to heat an
nlexa [21]

Answer:

9.430 * 10¹⁷ protons per second whill shine on the book from a 62 W bulb

Explanation:

To answer this question, first let's calculate the energy of a single photon with a wavelength (λ) of 504 nm:

E = hc/λ

Where h is Planck's constant (6.626*10⁻³⁴ J·s) and c is the speed of light (3*10⁸ m/s).

E = 6.626*10⁻³⁴ J·s * 3*10⁸ m/s ÷ (504*10⁻⁹m) = 3.944 * 10⁻¹⁹ J.

So now we can make the equivalency for this problem, that

<u>1 proton =  3.944 * 10⁻¹⁹ J</u>

Now we convert watts from J/s to proton/s:

1 \frac{J}{s}*\frac{1proton}{3.944*10^{-19}J}=2.535*10^{18} \frac{proton}{s} = 1 W

Solving the problem, a 62 W bulb converts 5% of its output into light, so:

  • 62 * 5/100 = 3.1 W

3.1 watts are equal to [ 2.535*10¹⁸ proton/s * 3.1 ] = 7.858 * 10¹⁸ proton/s

Of those protons per second, 12% will shine on the chemistry textbook, thus:

7.858 * 10¹⁸ proton/s * 12/100 = 9.430 * 10¹⁷ protons/s

8 0
2 years ago
Other questions:
  • Need help plzz
    8·1 answer
  • What is the element name for Fe?
    11·2 answers
  • Papa bless
    8·2 answers
  • How many elements are in 2CaCO3 and C8H10N402
    5·1 answer
  • Which one of these is a compound? a) air b) carbon dioxide c) oxygen and d) carbon
    10·2 answers
  • How many moles are in 6.8 x 10^23 molecules of NaOH? (show work please)
    6·1 answer
  • When a variable is determined by a factor outside of the function or model being​ evaluated, it is said to be A. statistically i
    7·1 answer
  • What happens to the particles during solid to a liquid
    11·1 answer
  • How many liters of oxygen gas, at STP, are produced by the decomposition of 0.605 moles of potassium chlorate? 2KClO3 ➞ 2KCl + 3
    8·1 answer
  • How many grams of calcium hydroxide is produced from 9.4 g of calcium chloride in this balanced
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!