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3 years ago

10

A company makes wax candles shaped like rectangular prisms. Each candle is 5 cm long, 3cm wide, and 10cm tall. If the company us

ed 3900 cm3 of wax, how many candles did they make?

1 answer:

sweet-ann [11.9K]3 years ago

8 0

Answer:

26 candles

Step-by-step explanation:

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3 years ago

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Evaluate each absolute value expression below | 2 | + | 4 | | − 3 | + | 5 | | − 7 | + | − 1 | − | 6 |

Bingel [31]

Answer:

44

Step-by-step explanation:

The absolute value symbols turn any negative inside of them to a positive, so your expression is ...

2 + 4·3 +5·7 +1 -6

= 2 +12 +35 +1 -6

= 44

4 0

4 years ago

Given these values<br> f(x)=x^2 -3x-4, g(x)=-2x, h(x)-x^3<br><br> Evaluate <br> (f(g(h(x)))

goldfiish [28.3K]

$\begin{cases} f(x)=x^2-3x-4\\ g(x)=-2x\\ h(x)=-x^3 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{g(~~h(x)~~)}{g(~~-x^3~~)}=-2\boxed{-x^3}\implies g(~~-x^3~~)=2x^3 \\\\[-0.35em] ~\dotfill\\\\ \underset{f(~~g(~~-x^3~~)~~)}{\stackrel{f(~~g(~~h(x)~~)~~)}{f(~~2x^3~~)}}=\boxed{2x^3}^2-3\boxed{2x^3}-4\implies f(~~2x^3~~)=2^2x^{3\cdot 2}-6x^3-4 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{f(~~g(~~h(x)~~)~~)}{f(~~2x^3~~)}=4x^6-6x^3-4~\hfill$

4 0

3 years ago

at a party 3/5 of the attendess were female . of the the female 2/5 wore earrings .what fraction of the attendees were femaleas

Nata [24]

$\frac{6}{25}$ of the attendees were females wearing earrings.

Step-by-step explanation:

As per the given information, there were $\frac{3}{5}$ females in the party.

To calculate the fraction of females wearing earrings we will do the following,

From these $\frac{3}{5}$ females, $\frac{2}{5}$ females wore earrings.

<u>This can be written in numerical form as:</u>

$\frac{2}{5}$ of $\frac{3}{5}$

---> $\frac{2}{5}$ * $\frac{3}{5}$

= $\frac{6}{25}$

So $\frac{6}{25}$ of the attendees were females wearing earrings.

Keywords: Fraction

Learn more about fractions at

#LearnwithBrainly

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3 years ago

In a certain triangle the base is 3/4 of the height (h). what is the area of the triangle in terms of h?

Nastasia [14]

A=1/2(h)(3/4h)
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3 years ago