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nevsk [136]
3 years ago
8

What should be done to lift the same

Physics
1 answer:
kari74 [83]3 years ago
7 0

Answer:

an inclined plane Makes easier to raise something heavy,like a rock. instead of lifting the rock straight up,you can raise it from its original Location with less force by pushing it up a ramp

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Help pls lol and tysm
Zanzabum

Answer:

umm section 2 and 4

Explanation:

because at section 2 it starts and at section 4 it moves again and stops at 3.

7 0
3 years ago
Two massless bags contain identical bricks, each brick having a mass M. Initially, each bag contains four bricks, and the bags m
stepladder [879]

Answer: F_{2}=\frac{3}{4}F_{1}

Explanation:

According to Newton's law of universal gravitation:

F=G\frac{m_{1}m_{2}}{r^2}

Where:

F is the module of the force exerted between both bodies

G is the universal gravitation constant.

m_{1} and m_{2} are the masses of both bodies.

r is the distance between both bodies

In this case we have two situations:

1) Two bags with masses 4M and 4M mutually exerting a gravitational attraction F_{1} on each other:

F_{1}=G\frac{(4M)(4M)}{r^2}   (1)

F_{1}=G\frac{16M^2}{r^2}   (2)

F_{1}=16\frac{GM^2}{r^2}   (3)

2) Two bags with masses 2M and 6M mutually exerting a gravitational attraction F_{2} on each other (assuming the distance between both bags is the same as situation 1):

F_{2}=G\frac{(2M)(6M)}{r^2}   (4)

F_{2}=G\frac{12M^2}{r^2}   (5)

F_{2}=12\frac{GM^2}{r^2}   (6)

Now, if we isolate \frac{GM^2}{r^2} from (3):

\frac{F_{1}}{16}=\frac{GM^2}{r^2}   (7)

Substituting \frac{GM^2}{r^2}  found in (7) in (6):

F_{2}=12(\frac{F_{1}}{16})   (8)

F_{2}=\frac{12}{16}F_{1}   (9)

Simplifying, we finally get the expression for F_{2}  in terms of F_{1} :

F_{2}=\frac{3}{4}F_{1}  

5 0
4 years ago
A 0.5kg pair of shoes weigh 0.3N on Pluto, what is the pull of gravity there?
lara [203]

Answer:

g= 0.6 m/s2

Explanation:

F = Mg

0.3 = 0.5g

g= 0.3/0.5

7 0
3 years ago
A 90 μC point charge is at the origin.
nikdorinn [45]

Answer:

a) E_1=4\times 10^6\ N.C^{-1}

b) E_3=202.5\ N.C^{-1}

Explanation:

Given:

charge at the origin, q=90\times 10^{-6}\ C

a)

Electric field at point (45\ cm,0\ cm):

The distance form the charge:

d_1=0.45\ m

Now the electric field at the given point:

E_1=\frac{1}{4\pi.\epsilon_0} \times \frac{q}{d_1^2}

E_1=9\times 10^9\times \frac{90\times 10^{-6}}{0.45^2}

E_1=4\times 10^6\ N.C^{-1}

b)

Electric field at point (-20\ cm, 60\ cm):

The distance form the charge:

d_3=\sqrt{(-20-0)^2+(60-0)^2}

d_3=63.2456\ m

Now the electric field at the given point:

E_3=\frac{1}{4\pi.\epsilon_0} \times \frac{q}{d_3^2}

E_3=9\times 10^9\times \frac{90\times 10^{-6}}{4000}

E_3=202.5\ N.C^{-1}

6 0
4 years ago
Technological design leads to the development and innovation of new technologies.
kakasveta [241]

Answer:

Solar panels have increased in efficiency over the past 20 years

Explanation:

Because if efficiency have increased other technologies will be discovered

7 0
3 years ago
Read 2 more answers
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