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Ivan
3 years ago
6

A navigational beacon in deep space broadcasts at a radio frequency of 50 MHz. A spaceship approaches the beacon with a relative

velocity of 0.40c. What is the frequency of the beacon radio signal that is detected on the ship
Physics
1 answer:
Mekhanik [1.2K]3 years ago
8 0

Answer:

The frequency heard y the ship is 70 MHz.

Explanation:

True frequency, f = 50 MHz

speed of source, vs = 0

speed of observer, vo = 0.4 c

Let the frequency heard by the ship is f'.

Use the formula of doppler's effect

f' = \frac{v +v_o}{v+ v_s}f\\\\f' = \frac{c + 0.4 c}{c}\times 50\\\\f' = 1.4\times 50\\​\\f' = 70 MHz

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A crate of mass 50kg is pushed along a floor with a force of 20N for a distance of
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2 years ago
If you connected 10 of these 12V (10 W) lamps in parallel, to the 12V source, how much current would the source have to supply
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Answer:

T=8.33A

Explanation:

From the question we are told that:

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Therefore

 R_{eq}=\frac{14.4}{10}

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Generally the equation for Current is mathematically given by

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2 years ago
What is the sidereal period used in Kepler’s third law?
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3 0
3 years ago
Certain neutron stars (extremely dense stars) are believed to be rotating at about 500 rev/s. If such a star has a radius of 17
Alexus [3.1K]

Answer:

7.22 × 10²⁹ kg

Explanation:

For the material to be in place, the gravitational force on the material must equal the centripetal force on the material.

So, F = gravitational force = GMm/R² where M = mass of neutron star, m = mass of object and R = radius of neutron star = 17 km

The centripetal force F' = mRω² where R = radius of neutron star and ω  = angular speed of neutron star

So, since F = F'

GMm/R² = mRω²

GM = R³ω²

M = R³ω²/G

Since ω = 500 rev/s = 500 × 2π rad/s = 1000π rad/s = 3141.6 rad/s = 3.142 × 10³ rad/s and r = 17 km = 17 × 10³ m and G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg²

Substituting the values of the variables into M, we have

M = R³ω²/G

M = (17 × 10³ m)³(3.142 × 10³ rad/s)²/6.67 × 10⁻¹¹ Nm²/kg²

M = 4913 × 10⁹ m³ × 9.872 × 10⁶ rad²/s²/6.67 × 10⁻¹¹ Nm²/kg²

M = 48,501.942 × 10¹⁵ m³rad²/s² ÷ 6.67 × 10⁻¹¹ Nm²/kg²

M = 7217.66 × 10²⁶ kg

M = 7.21766 × 10²⁹ kg

M ≅ 7.22 × 10²⁹ kg

8 0
2 years ago
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