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Ivan
3 years ago
6

A navigational beacon in deep space broadcasts at a radio frequency of 50 MHz. A spaceship approaches the beacon with a relative

velocity of 0.40c. What is the frequency of the beacon radio signal that is detected on the ship
Physics
1 answer:
Mekhanik [1.2K]3 years ago
8 0

Answer:

The frequency heard y the ship is 70 MHz.

Explanation:

True frequency, f = 50 MHz

speed of source, vs = 0

speed of observer, vo = 0.4 c

Let the frequency heard by the ship is f'.

Use the formula of doppler's effect

f' = \frac{v +v_o}{v+ v_s}f\\\\f' = \frac{c + 0.4 c}{c}\times 50\\\\f' = 1.4\times 50\\​\\f' = 70 MHz

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8 0
2 years ago
A mass M is suspended from a spring and oscillates with a period of 0.840 s. Each complete oscillation results in an amplitude r
iren [92.7K]

The energy becomes 0.50 times in 6.72 s.

Let E represent the oscillator's initial energy, Et be the energy's final value at time t, where A is its beginning amplitude, At amplitude at time t, be. as the oscillator's energy increases to 0.50 times its initial value. We can replace the oscillator's total energy for the energy at time t to obtain the amplitude as shown below.

Et=0.50E

1

k(4₂)² = (0.5) - kA²

(4₂)² = (0.5) A²

At = 0.71A

So, the amplitude of the oscillator becomes 0.71 times its initial ar

0.71A = = A(0.96)¹2

log(0.71)

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8.4

n=

So, the time taken for n oscillation is obtained as,

t = n (0.800 s)

= (8.4) (0.800)

= 6.72 s

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1 year ago
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3 years ago
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vazorg [7]

Answer:

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Explanation:

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Answer:

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Explanation:

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