Heat transfer in a closed system is the addition of changes in internal energy and the total amount of work done by it. The final energy of the system is 35.5kJ.
<h3>What is heat transfer? </h3>
Heat transfer is the transfer of heat energy due to temperature differences.
The paddle-wheel paintings are quantities of workdone, 500 N.m or 0.5kJ.
The preliminary (initial) power of the device is 10 kJ.
Total warmness transferred in the course of the method is 30 kJ
Total warmness misplaced in the course of the method to the encompassing air is 5 kJ.
The energy of the system is given as:
The energy of the system = Energy in - Energy out
The energy of the system = Initial energy + Energy transferred + Work done - Energy lost
Energy of the system = 10 + 30 + 0.5 - 5 kJ
Energy of the system = 35.5 kJ
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Answer:
a = 0.098 m/s²
Explanation:
The satellite, at any distance from the center of the Earth, is subject to the attractive force due to the Earth, according to the Newton´s Universal Law of gravitation, as follows:
Fg = G*ms*mE / (rse)²
According to Newton´s 2nd Law, neglecting any other force acted upon the satellite, we can write the following equation:
Fg = ms*a = G*ms*mE / (rse)²
⇒ a = G*mE / (rse)² (1)
As the distance between the satellite and the center of the Earth is 10 times the radius of the Earth, replacing this value in (1), we have:
a = G*mE / (10*RE)² = G*mE/(RE)² * (1/100)
but G*mE/(RE)², is just g, the acceleration due to gravity on the surface of the earth, so the gravitational acceleration due to Earth at satellite A, is as follows:
a = g*(1/100) = 0.01*g = 0.098 m/s²
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Explanation:
