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siniylev [52]
2 years ago
10

2. The longest snake ever found was a python that was 10.0 m long. Sup-

Physics
1 answer:
Akimi4 [234]2 years ago
8 0

Answer:

See below

Explanation:

Hypotenuse is snake length 10 m

   y coordinate = 10 sin 60 = 8.7 m

   x coordinate = 10 cos 60 =  5m

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WILL AWARD BEST ANSWER! find the current flowing across the 30 ohm resistor<br> i = _ a
Lelu [443]

0.143 A

Explanation:

The total resistance of the circuit is

r =  \frac{(40)(30)}{40 + 30}  +  \frac{(50)(20 + 10)}{50 + (20 + 10)}   \\ = 35.89 \: ohms

so the total current is

Itotal= V/R = 9V/35.89 ohms

= 0.25 A

To find the voltage drop across the 30-ohns resistor, use

V = Itotal × (combined resistance of 40 30)

= 0.25 A × 17.14 ohms = 4.285 volts

so the current through the 30-ohm resistor is

I = (voltage drop)/30-ohms

= (4.285 V)/(30 ohms)

= 0.143 A

6 0
3 years ago
The law of conservation of energy states that when one from of energy is converted into another ,
Dahasolnce [82]

B.

The law of conservation states that energy cannot be created nor destroyed

7 0
3 years ago
How long does it take to raise the temperature of the air in a good-sized living room (3.00m×5.00m×8.00m) by 10.0∘C? Note that t
QveST [7]

Answer : The time required is, 16.1 minutes.

Explanation :

First we have to calculate the amount of heat required to increase the temperature is:

Q=mC\Delta T\\\\Q=\rho VC\Delta T

(m=\rho V)

where,

Q = amount of heat required = ?

m = mass

\rho = density of air = 1.20kg/m^3

V = volume of air

C = specific heat of air = 1006J/kg^oC

\Delta T = change in temperature = 10.0^oC

Now put all the given values in above formula, we get:

Q=\rho VC\Delta T

Q=(1.20kg/m^3)\times (3.00m\times 5.00m\times 8.00m)\times (1006J/kg^oC)\times (10.0^oC)

Q=1.449\times 10^6J

Now we have to calculate the time required.

Formula used :

t=\frac{Q}{P}

where,

t = time required = ?

Q = amount of heat required = 1.449\times 10^6J

P = power = 1500 W

Now put all the given values in above formula, we get:

t=\frac{1.449\times 10^6J}{1500W}

t=966s\times \frac{1min}{60s}=16.1min

Thus, the time required is, 16.1 minutes.

3 0
3 years ago
A 1.20 g sample of an unknown has a volume of 1.73 cm what is the density of the unknown
mariarad [96]
1.73 divide by 1.20=1.4416
7 0
3 years ago
I need help now please help me
alexandr1967 [171]
The correct answer is C. Plug in x and y value for answers to see if they work. For example, 9/3 = 3. So C is the answer.
8 0
4 years ago
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