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siniylev [52]
2 years ago
10

2. The longest snake ever found was a python that was 10.0 m long. Sup-

Physics
1 answer:
Akimi4 [234]2 years ago
8 0

Answer:

See below

Explanation:

Hypotenuse is snake length 10 m

   y coordinate = 10 sin 60 = 8.7 m

   x coordinate = 10 cos 60 =  5m

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When it is summer at the South Pole,
Elza [17]
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The northern hemisphere is experiencing winter because it is tilted away from the sun whereas the south experiences summer because it is tilted towards the sun
6 0
3 years ago
An object initially at rest experiences an acceleration
lidiya [134]

Answer:

1.4m/s

Explanation:

Average velocity is the total distance covered divided by the total time taken.

 Average velocity  = \frac{total distance }{time }  

 Total time taken  = 5s + 6s  = 11s

The first distance covered  = velocity x time  = 1.4 x 5 = 7m

     second distance covered  = velocity x time  = 1.4 x 6  = 8.4m

So;

  Average velocity  = \frac{7 + 8.4}{11}    = 1.4m/s

5 0
3 years ago
A train whistle has a sound intensity level of 70. dB, and a library has a sound intensity level of about 40. dB. How many times
kodGreya [7K]

Answer:

The sound intensity of train is 1000 times greater than that of the library.

Explanation:

We have expression for sound intensity level,

            L=10log_{10}\left ( \frac{I}{I_0}\right )

A train whistle has a sound intensity level of 70 dB

We have

           70=10log_{10}\left ( \frac{I_1}{I_0}\right )

A library has a sound intensity level of about 40 dB

We also have

           40=10log_{10}\left ( \frac{I_2}{I_0}\right )

Dividing both equations

           \frac{70}{40}=\frac{10log_{10}\left ( \frac{I_1}{I_0}\right )}{10log_{10}\left ( \frac{I_2}{I_0}\right )}\\\\\frac{7}{4}=\frac{log_{10}\left ( \frac{I_1}{I_0}\right )}{log_{10}\left ( \frac{I_2}{I_0}\right )}\\\\10^7\frac{I_2}{I_0}=10^4\frac{I_1}{I_0}\\\\\frac{I_1}{I_2}=10^3=1000

The sound intensity of train is 1000 times greater than that of the library.

3 0
3 years ago
Two point charges of equal magnitude q are held a distance d apart. Consider only points on the line passing through both charge
NemiM [27]

let us consider that the two charges are of opposite nature .hence they will constitute a dipole .the separation distance is given as d and magnitude of each charges is q.

the mathematical formula for potential is V=\frac{1}{4\pi\epsilon} \frac{q}{d}

for positive charges the potential is positive and is negative for negative charges.

the formula for electric field is given as-E=\frac{1}{4\pi\epsilon} \frac{q}{r^2}

for positive charges,the line filed is away from it and for negative charges the filed is towards it.

we know that on equitorial line the potential is zero.hence all the points situated on the line passing through centre of the dipole and perpendicular to the dipole length is zero.

here the net electric field due to the dipole can not be zero  between the two charges,but we can find the points situated on the axial  line but  outside of charges where the electric field is zero.

now let the two charges of same nature.let these are positively charged.

here we can not find a point between two charges and on the line joining  two charges  where the potential is zero.

but at the mid point of the line joining two charges the filed is zero.

5 0
3 years ago
Which is a rule of boundary plates colliding or sliding past each other?
marissa [1.9K]

Explanation:

C...earthquakes occur

6 0
2 years ago
Read 2 more answers
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