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juin [17]
2 years ago
14

Write an equation for a line perpendicular to y=4x+1 and passing through the point (12,-7).

Mathematics
1 answer:
Gnoma [55]2 years ago
3 0

Answer:

Step-by-step explanation:

y = 4x + 1

Slope of line = 4

Slope of perpendicular to line = -¼

Point-slope equation for line of slope -¼ that passes through (12, -7):

y+7= -¼(x-12)

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Answer:

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Step-by-step explanation:

Substitution means plugging in one variable's value that consists of the opposite variable. Because y=3x-10 is already specified, you can plug it into the second equation's y value. After doing that, it looks like this:

-4x+2y=20→-4x+2(3x-10)=20

Then you would distribute the 3 across the parentheses next to it, like this:

-4x+2(3x-10)=20→-4x+6x-20=20

Then, add like terms, like this:

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Then divide both side by 2 to isolate x.

x=20

Now, you can plug 20 (x) into either equation, but the first one seems simpler so you would pick that. It would look like this:

y=3x-10→y=3(20)-10

Solving would look like this:

y=3(20)-10→y=60-10→y=50

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2 years ago
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