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topjm [15]
3 years ago
12

FUNCTIONS: In the space provided, type the answer in descending order as it applies without any spaces between the letters, numb

ers, or symbols.
Type the composition (fog)(x) of the given functions:
f(x) = x^2 + 2x − 6 and g(x) = x + 5.
Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
3 0

Answer:

Hence The composition (fog)(x) of the given function is x^2+12x+29.

Step-by-step explanation:

Given:

f(x) = x^2+2x-6

g(x)=x+5

We need to find (f o g)(x).

Solution:

Now we can say that;

(f o g)(x) = f(g(x))

(fog)(x) = (x+5)^2+2(x+5)-6

Now Applying distributive property we get;

(fog)(x) = (x+5)^2+2\times x+2\times5-6\\\\(fog)(x) = (x+5)^2+2x+10-6\\\\(fog)(x) = (x+5)^2+2x+4

Now Solving the exponent function we get;

(fog)(x) = x^2+2\times x\times 5+5^2+2x+4\\\\(fog)(x) = x^2+10x+25+2x+4\\\\(fog)(x) = x^2+12x+29

Hence The composition (fog)(x) of the given function is x^2+12x+29.

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GrogVix [38]

You would do 4 divided by 3. Which is 1.33 with repeating 3s. You would then round to the nearest hundredth which would 1.33. You can multiply 1.33 and 3 to check your work. Although it might not exactly 4 it is not that big of a deal.

Hope this helps!

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HELP ASAP!! Identify the matrix transformation of ΔPQR, which has coordinates P(−5, −2),Q(−6, −3), and R(−2, −3), for reflection
podryga [215]

Answer:

Matrix transformation = \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]

Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)

Step-by-step explanation:

Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right].

To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:

P'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-5\\-2\end{array}\right]= (5,-2)

Q'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-6\\-3\end{array}\right]= (6,-3)

R'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-2\\-3\end{array}\right]= (2,-3)

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Lana71 [14]
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