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2 years ago

Find the value of x. 3) 2x (x + 21)

Mathematics

1 answer:

Xelga [282]2 years ago

5 0

To find the x-intercept, substitute in

for

and solve for

. To find the y-intercept, substitute in

for

and solve for

x-intercept(s):

(

)

(

−

)

y-intercept(s):

(

)

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Tim ate 5/7 of a cake . ket ate 7/11 of a cake. who ate more cake ? how much more?

Dmitry_Shevchenko [17]

5/7 simplifies to 0.714. 7/11 simplifies to 0.636. Therefore, Tim ate about 1.1224 times more cake than Ket.

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4 years ago

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C) How could you use estimation to determine if your answer is reasonable? Explain.

Sliva [168]

Estimation would give you an answer close to the actual answer so you can see if your answer is reasonable depending on how close the estimate is

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2 years ago

Are the ratios 20:16 and 5:4 equivalent?

emmasim [6.3K]

Answer:

Yes

Step-by-step explanation:

20:16

Reduce the ratio to lowest terms by dividing both numbers by 4.

20:16 = 5:4

Answer: Yes

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2 years ago

Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46

JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

$M = \frac{50463-38737}{2} = 5863$

Relating the margin of error with the sample size:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.64.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

For this problem, we have that $\sigma = 14300, M = 5863$ . So

$M = z\frac{\sigma}{\sqrt{n}}$

$5863 = 1.645\frac{14300}{\sqrt{n}}$

$5863\sqrt{n} = 1.645*14300$

$\sqrt{n} = \frac{1.645*14300}{5863}$

$(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2$

$n = 16$

The sample size was of 16.

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3 years ago

If 10 candy cost $35. How much candy can I buy with $20

Alika [10]

Answer:

6 candies

Step-by-step explanation:

(find unit rate, cost / quantity)

35/10 = 3.5

20/3.5 = = 5.7142857142857

candies cannot be in decimal so you must round to the nearest whole

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3 years ago

Find the value of x. 3) 2x (x + 21)​

Find the value of x. 3) 2x (x + 21)