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dsp73
2 years ago
10

Find the value of x. 3) 2x (x + 21)​

Mathematics
1 answer:
Xelga [282]2 years ago
5 0

To find the x-intercept, substitute in

0

for

y

and solve for

x

. To find the y-intercept, substitute in

0

for

x

and solve for

y

.

x-intercept(s):

(

0

,

0

)

,

(

−

21

,

0

)

y-intercept(s):

(

0

,

0

)

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Rewrite in simplest terms: -4(5v – 3v – 6) – 9v
julsineya [31]

Answer:

-4 (5v -3v -6) -9v (use the distributive property)

-20v +12v +24 -9v (combine all like terms)

-17v +24

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An office manager needs to decide between two tables for the conference room. One is rectangular, 5 feet wide by 10 feet long. T
zvonat [6]
Radius of circle= 4

a) circle circumference=2(pi)r
circumference=2(pi)4=25.13

P=2W+2L
p=2(5)+2(10)
P=30

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area of rectangle=L×W= 5×10= 50

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5 0
3 years ago
Which histogram represents the data?
Darina [25.2K]
Top right, it’s really easy just. Count the numbers
4 0
3 years ago
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Find the vertical and horizontal asymptotes, domain, range, and roots of f (x) = -1 / x-3 +2.
gladu [14]

Answer:

Vertical asymptote: x=3

Horizontal asymptote: f(x) =2

Domain of f(x) is all real numbers except 3.

Range of f(x) is all real numbers except 2.

Step-by-step explanation:

Given:

Function:

f (x) = -\dfrac{1 }{ x-3} +2

One root, x = 3.5

To find:

Vertical and horizontal asymptote, domain, range and roots of f(x).

Solution:

First of all, let us find the roots of f(x).

<em>Roots of f(x) means the value of x where f(x) = 0</em>

0= -\dfrac{1 }{ x-3} +2\\\Rightarrow 2= \dfrac{1 }{ x-3}\\\Rightarrow 2x-2 \times 3=1\\\Rightarrow 2x=7\\\Rightarrow x = 3.5

One root, x = 3.5

Domain of f(x) i.e. the values that we give as input to the function and there is a value of f(x) defined for it.

For x = 3, the value of f(x) \rightarrow \infty

For all, other values of x , f(x) is defined.

Hence, Domain of f(x) is all real numbers except 3.

Range of f(x) i.e. the values that are possible output of the function.

f(x) = 2 is not possible in this case because something is subtracted from 2. That something is \frac{1}{x-3}.

Hence, Range of f(x) is all real numbers except 2.

Vertical Asymptote is the value of x, where value of f(x) \rightarrow \infty.

-\dfrac{1 }{ x-3} +2 \rightarrow \infty

It is possible only when

x-3=0\\\Rightarrow x=3

\therefore vertical asymptote: x=3

Horizontal Asymptote is the value of f(x) , where value of x \rightarrow \infty.

x\rightarrow \infty \Rightarrow \dfrac{1 }{ x-3} \rightarrow 0\\\therefore f(x) =-0+2 \\\Rightarrow f(x) =2

\therefore Horizontal asymptote: f(x) =2

Please refer to the graph of given function as shown in the attached image.

5 0
3 years ago
Find the area. The figure is not drawn to scale.
BARSIC [14]

Answer:

A

Step-by-step explanation:

40 x 36 = 1440 in.2

7 0
3 years ago
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