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3 years ago

Let a be a nonzero rational number. Is rational or irrational? Prove your answer by picking a value for a and simplifying

Mathematics

1 answer:

Kobotan [32]3 years ago

3 0

Answer:

there is no expression to answer this based off of

Step-by-step explanation:

we can't answer an incomplete question sorry try again and maybe then

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Explain the cyclin-dependent regulation<br>cell cycle<br>

insens350 [35]

Cyclins drive the events of the cell cycle by partnering with a family of enzymes called the cyclin-dependent kinases (Cdks). A lone Cdk is inactive, but the binding of a cyclin activates it, making it a functional enzyme and allowing it to modify target proteins.

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3 years ago

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3 years ago

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PLEASE HELP FAST!!! While bisecting a line segment, Kara has just drawn two arcs, one passing through each endpoint. Which of th

GuDViN [60]

Answer:

Kara should plot points where the arcs intersect above and below the line segment.

Step-by-step explanation:

The bisection of a line segment is the dividing of the line segment into two equal parts. To bisect a line segment, you have place your compass on the endpoints and measure a distance greater than half of the segment. The point of intersection of the arcs both above and below the segment is then joined thereby bisecting the line.

Since Kara has already drawn the two arcs which are greater that half of the length, all Kara needs to do is plot points where the arcs intersect above and below the line segment.

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3 years ago

I cant seem to get one of these answers when i work it out. please help

lisov135 [29]

Answer:

first option

Step-by-step explanation:

To obtain ( f ￮ g)(x) substitute x = g(x) into f(x) , that is

f( $\frac{1}{2x}$ )

= $\frac{2}{\frac{1}{2x}+3 }$ ( multiply numerator/ denominator by 2x to clear the fraction

= $\frac{2(2x)}{2x(\frac{1}{2x}+3) }$

= $\frac{4x}{1+6x}$

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3 years ago

What 2 numbers add to get 2 and multiply to 4

rusak2 [61]

Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x= $\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a}$ so

1x^2-2x+4=0
a=1
b=-2
c=4
x= $\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}$
x= $\frac{ 2+/-\sqrt{4-16} }{2}$
x= $\frac{ 2+/-\sqrt{-12} }{2}$
we have $\sqrt{-12}$ and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x= $\frac{ 2+/-2\sqrt{-3} }{2}$
i= $\sqrt{-1}$
x= $\frac{ 2+/-2i\sqrt{3} }{2}$
x= $1+/-i\sqrt{3}$
x= $1-i\sqrt{3}$ or x= $1+i\sqrt{3}$ (those are the 2 numbers)

6 0

4 years ago