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2 years ago

4 The formula for the volume of a sphere is V= 3 #rº. What is the formula solved for r?

Mathematics

1 answer:

Blizzard [7]2 years ago

6 0

Answer:

B. r = 3√(3V - 4π)

Step-by-step explanation:

volume of a sphere,V = 4/3πr³

Solve for r

V = 4/3πr³

V - 4/3π = r³

r³ = V - 4π/3

Cross product

r³ = V*3 - 4π

r³ = 3V - 4π

Find the cube root of both sides

3√r³ = 3√(3V - 4π)

r = 3√(3V - 4π)

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Use bayes's rule to find the probability that a child from this population who has inadequate intake is 11 to 13 years old.

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Answer:

Step-by-step explanation:

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3 years ago

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2 years ago

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2 years ago

Find the volume of the rectangular prism. 19 cm 9 cm 2 cm

Makovka662 [10]

Answer: 342 cm³

Step-by-step explanation: To find the volume of the rectangular prism, start with the formula for the volume or a prism.

Volume = length × width × height

Since we are not sure what the length, width, or height is in this problem, we can plug any of these numbers in for the length, width, or height. The commutative property of multiplication states that changing the order of the factors does not change the product.

Volume = (19 cm) (9 cm) (2 cm)

Volume = 342 cm³

Therefore, the volume of the rectangular prism is 342 cm³.

5 0

3 years ago

The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

olya-2409 [2.1K]

Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

At x = 50 units,

$\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$

3 0

2 years ago