Answer:
3)5x-4y=-3
6x+4y=14
Step-by-step explanation:
The system of equations is given
5x-4y=-3
3x+2y=7
Multiplying both sides of the lower equation by 2, we get
6x + 4y = 14
That means your answer 3)
I would say your friends assumption is wrong. Why?
Because, if you payed $2.40 for 3/4 pounds of grapes, your friend should pay more for an entire pound, not less.
Hope this helped! c:
Given:
Point F,G,H are midpoints of the sides of the triangle CDE.
To find:
The perimeter of the triangle CDE.
Solution:
According to the triangle mid-segment theorem, the length of the mid-segment of a triangle is always half of the base of the triangle.
FG is mid-segment and DE is base. So, by using triangle mid-segment theorem, we get
GH is mid-segment and CE is base. So, by using triangle mid-segment theorem, we get
Now, the perimeter of the triangle CDE is:
Therefore, the perimeter of the triangle CDE is 56 units.
Answer:
Step-by-step explanation:
The salaries are the same. Only the fraction of how much is saved is quite different.
Equation
x ( 9/11 - 7/9) = 1584
Explanation: The salary amount is x. The fractional amounts saved are also given. You have to take the difference because one of the people saves more than the other.
The amount that is more is 1584.
Solution
9/11 = 0.8182
7/9 = 0.7778
9/11 - 7/9 = 0.8182 - 0.7778 = 0.0404
Put that into the equation.
x(0.0404) = 1584 Divide by 0.0404)
x(0.0404) = 1584/0.0404
answer:x = 39204
Well, first off, to solve for this, we can write the expression and then solve from there.
Expression: 8x + 3 = 29
So, now that we have our expression, we can solve for our missing number using the balancing method.
8x + 3 = 29
8x + 3 - 3 = 29 - 3 (we subtracted the three because we needed to get rid of the three on the left side of the equation do now we are just left with 8x = 26.
8x = 26
8x/8 = 26/8. (So, the 8 on the left side cancels out and we are just left with X.
X = 26/8
X = 13/4
X = 3 and 1/4
So, in conclusion, the answer to this question is: X = 3 and 1/4 as a mixed number or 13/4 as an improper fraction.
Glad I could help!
