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Solnce55 [7]
3 years ago
8

Tina is planning to fence in an area for her dog. She wants to create a rectangular area of 1,600 square feet for her pet and ca

n afford to purchase 160 feet of fence. In two or more complete sentences, explain the algebraic model, calculations and reasoning necessary to determine the dimensions of the rectangular area
Mathematics
1 answer:
natima [27]3 years ago
5 0

1 Area is 1600 =a*b2. Perimeter is 2(a+b)=160 ==>b=80-a
So,1600=a*b=a*(80-a)==>80a-a²=1600==> a²-80a+1600=0==> (a-40)²=0==>a=40 or a=-40 (to exclude since <0)==>b=1600/40=40The rectangle is a square of 40m of side.
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Answer: 76

Step-by-step explanation:

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3 years ago
Y=x^2-2x-8
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1. (1,-9)

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Solve the following equations by factorisation method.Only factorisation not dharacharya.​
Luba_88 [7]

Hello, please consider the following.

When x_1 and x_2 are two roots, we can factorise as

ax^2+bx+c=a(x-x_1)(x-x_2)=a(x^2-(x_1+x_2)x+x_1x_2)=0

So for the first equation, we can say that the sum of the zeros is

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and the product is

\dfrac{a^2b^2}{4}=\dfrac{a^2}{2}\dfrac{b^2}{2}

So we can factorise as below.

4x^2-2(a^2+b^2)x+a^2b^2=(2x-a^2)(2x-b^2)=0

And the solutions are

\boxed{\sf \n\bf  \ \dfrac{a^2}{2} \ \ and \ \ \dfrac{b^2}{2}}

For the second equation, we will complete the square and put the constant on the right side and take the root.

Let's do it!

9x^2-9(a+b)x+2a^2+5ab+2b^2=0\\\\9(x-\dfrac{a+b}{2})^2-9\dfrac{(a+b)^2}{4}+2a^2+5ab+2b^2=0\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{9(a+b)^2-8a^2-20ab-8b^2}{4}\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{9a^2+18ab+9b^2-8a^2-20ab-8b^2}{4}\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{a^2+b^2-2ab}{4}=\dfrac{(a-b)^2}{4}\\\\(x-\dfrac{a+b}{2})^2=\dfrac{(a-b)^2}{2^2\cdot 3^2}

We take the root, and we find the two solutions

\begin{aligned}x_1&=\dfrac{a+b}{2}-\dfrac{a-b}{6}\\\\&=\dfrac{3a+3b-a+b}{6}\\\\&=\dfrac{2a+4b}{6}\\\\&\boxed{=\dfrac{a+2b}{3}}\end{aligned}

\begin{aligned}x_1&=\dfrac{a+b}{2}+\dfrac{a-b}{6}\\\\&=\dfrac{3a+3b+a-b}{6}\\\\&=\dfrac{4a+2b}{6}\\\\&\boxed{=\dfrac{2a+b}{3}}\end{aligned}

Thank you.

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Two decimal numbers, both less than 1, are multiplied. The product is:
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Answer:

B. Always less than one

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