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Solnce55 [7]
2 years ago
8

Tina is planning to fence in an area for her dog. She wants to create a rectangular area of 1,600 square feet for her pet and ca

n afford to purchase 160 feet of fence. In two or more complete sentences, explain the algebraic model, calculations and reasoning necessary to determine the dimensions of the rectangular area
Mathematics
1 answer:
natima [27]2 years ago
5 0

1 Area is 1600 =a*b2. Perimeter is 2(a+b)=160 ==>b=80-a
So,1600=a*b=a*(80-a)==>80a-a²=1600==> a²-80a+1600=0==> (a-40)²=0==>a=40 or a=-40 (to exclude since <0)==>b=1600/40=40The rectangle is a square of 40m of side.
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Could someone please help me with this problem? I don't understand.
sasho [114]
Try dividing 150 by 2 1/2 and your answer would be 6.25 you may want to double check that math though
4 0
3 years ago
Question 1
777dan777 [17]

Answer:

There would be 94 tiles.

Step-by-step explanation:

The number of tiles is given by the following equation:

n = 6 + 4p

In which p is the current position.

How many tiles would there be in position 22?

This is n when p = 22. So

n = 6 + 4*22 = 6 + 88 = 94

There would be 94 tiles.

8 0
2 years ago
A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
2 years ago
A diving board is 10 feet above the surface of the water. At time t = 0, the board propels Chris upward at a rate of 12 feet per
Art [367]

Answer:

Chris will take 0.75 seconds to return to his starting height of 10 feet.

Step-by-step explanation:

Let the height of Chris be represented by h(t) = -16\cdot t^{2}+12\cdot t +10, where h(t) is the height in feet and t, the time in seconds. First, we equalize the formula to a height of 10 feet and simplify the resulting expression, that is:

-16\cdot t^{2}+12\cdot t +10 = 10

-16\cdot t^{2}+12\cdot t = 0

Then, we simplify the expression by algebraic means:

-16\cdot t\cdot \left(t-\frac{3}{4} \right) = 0

Roots of the polynomial are, respectively:

t = 0\,s\,\lor \,t = 0.75\,s

First root represents the initial height of Chris, whereas the second one represents the instant when Christ returns to the same height above the surface of the water. Hence, Chris will take 0.75 seconds to return to his starting height of 10 feet.

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They would have to pay the hourly cost if they played around 7 games because 7 games would equal to the cost of one hour.
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