Did you figure it out? I really need to know :( @Hope491
F(x) = 6/x is to be translated down 8 units and left 2 units. It will become
f(x +2) -8
y = 6/(x +2) -8
(x-h)^2 + (y-k)^2 = r^2
r=3
(x-h)^2 + (y-k)^2 = 3^2
the center lies on the y-axis --> h=0
x^2 + (y-k)^2 = 3^2 = 9
expand
x^2 + y^2 -2ky + k^2 = 9
x^2 + y^2 -2ky + (k^2 - 9) = 0
compare to general form
A=1 , B=1 and C =0
D= -2k and E=k^2 - 9
<span>cos x = [ e^(ix) - e^(-ix) ] / 2i along with [ A - B ]^5 =
( A^5 - B^5) - 5 AB ( A^3 - B^3) + 10 A²B² (A - B )...A = e^(ix) , B = e^(-ix)
[ cos x ] ^5 = (1/32i) { [ e^(5ix) - e^(-5x) ] - 5 [ ( e^(3ix) - e^(-3ix) ] + 10 [ e^(ix) - e^(-ix) ] }
= ( 1 / 16 ) { cos 5x - 5 cos 3x + 10 cos x }.....much faster</span>
