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3 years ago

Is a triangle with side lengths of 5, 10, and 15 a right triangle? Explain

2 answers:

german3 years ago

7 0

If triangle is a right triangle we can use Pythagorean theorem, c^2=a^2+b^2
c=15, a=5, b=10
15^2=5^2+10^2
225=25+100
225=125
225 is not equal to 125 therefore, this triangle is not a right triangle.

Harrizon [31]3 years ago

3 0

Answer:

No, it is not a right triangle.

Step-by-step explanation:

Using the property of the right triangle, square root (5^2 + 10^2) = 5root(5), and it is not equal to 15, so it is not a right triangle.

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Varvara68 [4.7K]

The answer is seventy two

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2 years ago

For what value of a does (1/9)a+1 =81a+1 272-a?

AlexFokin [52]

Answer:

-4

Step-by-step explanation:

$\left( \dfrac{1}{9}\right)^{a+1}= 81^{a+1}\cdot 27^{2-a}\\\\\\(3^{-2})^{a+1}=(3^4)^{a+1}\cdot (3^3)^{2-a} \\\\\\3^{-2a-2}=3^{4a+4}\cdot 3^{6-3a} \\\\\\3^{-2a-2}=3^{a+10} \\\\\\-2a-2=a+10 \\\\\\-3a=12 \\\\\\a=-4$

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2 years ago

One Sunday, 120 days before Christmas, Aldsworth store publishes an advertisement saying ‘120 shopping days until Christmas'. Al

Lena [83]

Answer:

(a)18

(b)1089

(c)Sunday

Step-by-step explanation:

The problem presented is an arithmetic sequence where:

First Sunday, a=1
Common Difference (Every subsequent Sunday), d=7

We want to determine the number of Sundays in the 120 days before Christmas.

(a)In an arithmetic sequence:

$\text{The nth term}, T_n=a+(n-1)d\\T_n \leq 120\\$Therefore:$\\1+7(n-1) \leq 120\\1+7n-7\leq 120\\7n-6\leq 120\\7n\leq 120+6\\7n\leq 126\\$Divide both sides by 7$\\n\leq 18$

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.

Therefore, Aldsworth advertised 18 times.

(b)Next, we want to determine the sum of the first 18 terms of the sequence

1,8,15,...

$\text{Sum of a sequence}, S_n=\frac{n}{2}( 2a+(n-1)d)\\S_{18}=\frac{18}{2}( 2*1+(18-1)*7)\\=9(2+17*7)\\=9(2+119)\\=9*121\\S_{18}=1089$

The sum of the numbers of days published in all the advertisements is 1089.

(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.

6 0

2 years ago

Do you guys know this?

tiny-mole [99]

Answer: b and d im sure

Step-by-step explanation:

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2 years ago

I NEED ANSWERS FAST Laura bought 8 3/10 yd of ribbon. She used 1 ⅖ yd to tie a package and 2 ⅓ yd to make a bow. Joe later gave

sergejj [24]

Answer:

9 1/6 yd

Step-by-step explanation:

First, list the lengths of ribbon Laura had or acquired:

8 3/10 yd + 4 3/5 yd. This is equivalent to 8 3/10 yd + 4 6/10 yd, or

12 9/10 yd.

Next, list the lengths of ribbon Laura used:

1 2/5 yd + 2 1/3 yd. The LCD here is 15, so we have 1 6/15 yd + 2 5/15 yd.

Summing up, we get 3 11/15 yd.

Subtract this length from the original 12 9/10 yard with which Laura began:

12 9/10 yd or 12 27/30 yd (LCD is 30)

- 3 11/15 yd or -3 22/30 yd

Subtracting the latter two quantities, we get 9 5/30 yd, or 9 1/6 yd

7 0

2 years ago