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Orlov [11]
3 years ago
10

The larger of two numbers is four more than the smaller. if the larger is x what is the smaller?

Mathematics
1 answer:
Lelu [443]3 years ago
4 0

Answer:

x-4

Step-by-step explanation:

Since the larger of two numbers is four more than the smaller one, this means that there is a difference of 4 between the two numbers. In order to find the smaller of both numbers, you can obtain the smaller from the largest by subtracting 4.

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10-2(2x+1)=4(x-2)solve each equation for x graph your Solution on a number line ​
stepladder [879]

Answer:

No solution

Step-by-step explanation:

Actually, you have only one equation here.  We will solve it for x.

Performing the indicated multiplication, we obtain:

10-2(2x+1)=4(x-2)  =>  10 - 4x - 2 = 4x - 8, or 10 - 2 = -8.  This can never be true, so this equation has no solution.

6 0
3 years ago
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Matt's Mechanics charges $45.95 per hour to do a car repairs plus $30.50 for waste disposal. Write an equation to represent this
katrin2010 [14]

Answer:

45.95x + 30.50

Step-by-step explanation:

<u>Step 1:  Convert words into an expression</u>

Matt's Mechanics charges $45.95 per hour to do a car repairs plus $30.50 for waste disposal.

<em>45.95x + 30.50</em>

<em />

Answer:  45.95x + 30.50

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3 years ago
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Jane has a checkbook balance of $68.00. She then writes two checks one for $5.00 and one for $62.50. She also deposits $75.00 th
Sunny_sXe [5.5K]
The answer here would be <span>ON/C 6 8 – 5 – 6 2 . 5 0 + 7 5 =</span>
4 0
3 years ago
Use this information to answer the questions. University personnel are concerned about the sleeping habits of students and the n
Oksanka [162]

Answer:

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

p_v =P(Z>2.097)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

Step-by-step explanation:

1) Data given and notation

n=377 represent the random sample taken

X=209 represent the students reported experiencing excessive daytime sleepiness (EDS)

\hat p=\frac{209}{377}=0.554 estimated proportion of students reported experiencing excessive daytime sleepiness (EDS)

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.5:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.097)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

6 0
3 years ago
Warren, a golf fan, was curious about how often professional golfers make successful putts from various distances. He looked at
anzhelika [568]

Answer:

Explained below.

Step-by-step explanation:

A correlation coefficient is a mathematical measure of certain kind of correlation, in sense a statistical relationship amid two variables

Negative correlation is a relationship amid two variables in which one variable rises as the other falls, and vice versa.  

Values amid 0.7 and 1.0 (-0.7 and -1.0) implies a strong positive (negative) linear relationship amid the variables.

It is provided that Warren noticed a strong negative linear relationship between the success rate and putt distances.

This implies that as the putt distances are increasing the success rates are decreasing and as the putt distances are decreasing the success rates are increasing.

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3 years ago
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