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Veronika [31]
3 years ago
8

The Extreme Rock Climbing Club planned a climbing expedition. The total cost was $1400, which was to be divided equally among th

e members going. Prior to the trip, 3 members decided not to go. If the cost per person increased by $105, how many people went on the expedition?
Mathematics
2 answers:
Helen [10]3 years ago
8 0
To find the rate per person, we divide the additional $105 by the three people who backed out. The quotient would be 35. Hence, each person should pay $35. To determine how many people went to the expedition, divide the $1400 + $105 by 35, the answer is 43. Since 3 backed out, then the total number who actually went was 40.
julia-pushkina [17]3 years ago
3 0

Answer:

5 people

Step-by-step explanation:

Let

  • x = number of people
  • y = cost per person

The total cost was $1400, which was to be divided equally among the members going. Then,

y = 1400 / x [1]

Prior to the trip, 3 members decided not to go. The cost per person increased by $105.

y + 105 = 1400 / (x - 3)

(y + 105) . (x - 3) = 1400 [2]

We replace [1] in [2],

(1400/x + 105) . (x - 3) = 1400

1400 - 4200/x + 105x -315 = 1400

- 4200/x + 105x = 315

(- 4200 + 105x²)/x = 315

- 4200 + 105x² = 315 x

105x² - 315x - 4200 = 0

When we solve this quadratic equation using the quadratic formula, we get x₁ = 8 and x₂ = -5. Only the positive x has sense.

The people that went to the expedition was x - 3 = 8 - 3 = 5.

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Step-by-step explanation:

6 0
2 years ago
John is making baked goods for a party. He can either make muffins or bread, and he can use blueberries, bananas, apples, or cho
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The total number of possible choices that John had for making baked goods for the party is 8.

<h3>What is Combination?</h3>

The combination helps us to know the number of ways an object can be arranged without a particular manner. A combination is denoted by 'C'.

^nC_r = \dfrac{n!}{r!(n-r)!}

where,

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r is the choices to be made.

We know that the number of choices with John for his baked goods is only two which are muffins or bread, therefore, the choices of the baked good can be written as ^2C_1.

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Now, the total possible choices that John had

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Hence, the total number of possible choices that John had for making baked goods for the party is 8.

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