Proof
Provide the missing reasons for the proof of part of the triangle midsegment theorem.
Given: K is the midpoint of MJ.
L is the midpoint of NJ.
Prove: MN = 2KL
The complete answer is attached in the diagram below.
The complete answer for the missing reasons is attached below in the diagram.
Please check the figure.
Keywords: statement, proof, reason
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Answer:
Step-by-step explanation:
Sum of interior angle of any polygon = 180* (n- 2 )
Here, n= number of sides
Sum of interior angles of regular octagon = 180 * ( 8-2) = 180 * 6 = 1080°
In regular octagon, all the angles are congruent,
So, measure of an interior angle of regular octagon = 1080/8 = 135°
Sum of interior angles of regular hexagon = 180 * ( 6-2) = 180*4 = 720°
In regular hexagon, all the angles are congruent,
So, measure of an interior angle of regular hexagon = 720/6 = 120°
The measure of an interior angle of a regular octagon is greater than the measure of an interior angle of a regular hexagon by 15°
I'm pretty sure there were 48 girls at the beach clean up. 43 ÷ 7 = 6.14 (6 cause there's not gonna be floating males with missing body parts). So we multiply 6 x 8 and we get 48.
The factors of 7are -1 and 7 or 1 and -7, the factors of 14 are 1, 2, 7, and 14, or -1, -2, -7,-14. so the list of potential zeros are: 1/1, 1/2, 1/7, 1/14, 7/1,7/2, 7/7, 7/14, which can be simplified into 1, 1/2,1/7, 1/14, 7, 7/2
add the negative ones: -1, -1/2,-1/7, -1/14, -7, -7/2
I believe there are a total of 12 potential zeros
reference:
http://www.sparknotes.com/math/algebra2/polynomials/section4.rhtml
Answer:
I think B 82.3%
Step-by-step explanation: