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Nostrana [21]
3 years ago
6

Help please!!!!!! I don’t know how to do this

Mathematics
1 answer:
netineya [11]3 years ago
7 0

Answer:

x \leqslant  - 8

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Does the mapping diagram represent a function? Why or why not?
borishaifa [10]

Answer:

The answer is B

Step-by-step explanation:

In a function every X must have only 1 Y. In this example the x 3 has to y's 10 and 5, therefore making it not a function.

8 0
3 years ago
Which of the following is the graph of y=- square root x+1
maks197457 [2]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y=-\sqrt{x+1}

Find the intercepts

<u>The y-intercept</u> is the value of y when the value of x is equal to zero

so

For x=0 -----> y=-\sqrt{0+1}=-1

The y-intercept is the point (0,-1)

<u>The x-intercept </u>is the value of x when the value of y is equal to zero

so

For y=0 -----> 0=-\sqrt{x+1} ----->x=-1

The x-intercept is the point (-1,0)

<em>Find the domain</em>

we know that

The radicand must be positive

so

x+1\geq0

x\geq-1

All real numbers greater than or equal to -1

The range is all real numbers less than or equal to -1

using a graphing tool

see the attached figure

4 0
2 years ago
Read 2 more answers
Need help with ASAP!
Evgesh-ka [11]

Answer: 8y^6x^6

Step-by-step explanation:

Volume = l*w*h so multiply all the variable by <u>multiplying the numbers and adding the exponents</u> so

2y^2*4x^4y=8y^3x^4

then 8y^3x^4*x^2y^3=8y^6x^6

8 0
2 years ago
Read 2 more answers
Topic: Recognizing Linear and Exponential and Quadratic Functions.
BigorU [14]

Answer:

  Recursive: f(1) = 1; f(n) = f(n-1)/3

  Equation: f(x) = 5/3·(1/3)^(x-1)

Step-by-step explanation:

You know this is an exponential function because sequential lines in the table have a common ratio of f(x) values:

  f(2)/f(1) = (5/9)/(5/3) = 3/9 = 1/3

  f(3)/f(2) = (5/27)/(5/9) = 9/27 = 1/3

and it continues like that.

Besides telling you the function is exponential, it also tells you that each term is 1/3 of the previous term.

<h3>Recursive formula</h3>

The value of f(1) is read from the table. For x = 1, that value is ...

  f(1) = 5/3

As we noticed above, each term is 1/3 the previous term, so the recursive relation is ...

  f(n) = (1/3)·f(n-1)

<h3>Equation</h3>

The general form of the equation for a geometric (exponential) relation is ...

  f(x) = f(1)·r^(x-1) . . . . . . where f(1) is the first term, and r is the common ratio

For this function, we have f(1) = 5/3 and r = 1/3, so the equation is ...

  f(x) = 5/3·(1/3)^(x-1)

__

<em>Additional comment</em>

When given values of x that count from 1, we often express the equation in terms of (x-1). That equation can be simplified so the exponent is x.

  f(x) = 5·(1/3)^x

5 0
1 year ago
Solve the equation 3=4-5\root(3)(x^(8))
Anna35 [415]

Answer:

There is no values of x that make the equation true.

Step-by-step explanation:

I might be wrong but I found no solutions for this.

7 0
3 years ago
Read 2 more answers
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