Answer:
◦•●◉these are related functions
4 years old is the answer i think
Let x = length of side of the square. Then area of the square is
A(x) = x^2
You are also told that dx/dt = 6 cm/s
Now, you want to find dA/dt when A = 16, i.e., when x = 4.
Since
dx/dt = 6cm/s
and
dA/dx = 16cm/s
dA/dx dx/dt
= dA/dt
dA/dt A' = 2xx'
A' = 2x6cm/s
So we need to solve for x because we are trying to find dA
<span>so
</span>16 = x^(2)
(16)^(1/2) = 4
<span>thus
</span>
A' = 2(4)(6)
A' = 48
First divid 175 into 2 =87..5 than subtract 87.5 into 225 = 137.5
Answer:
absolute max=
(4.243,18)
absolute min =(-1,-5.916)
absolute max=(pi/6, 2.598)
absolute min = (pi/2,0)
Step-by-step explanation:
a)
To find max and minima in the given interval let us take log and differentiate
It is sufficient to find max or min of Y
In the given interval only 4.243 lies
And we find this is maximum hence maximum at (4.243,18)
Minimum value is only when x = -1 i.e. -5.916
b)
Equate I derivative to 0
-2sint +1-2sin^2 t=0
sint = 1/2 only satisfies I quadrant.
So when t = pi/6 we have maximum
Minimum is absolute mini in the interval i.e. (pi/2,0)