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Stels [109]
3 years ago
6

Does - 5 or 5 satisfy the equation x + 5 = 0 ?

Mathematics
2 answers:
-BARSIC- [3]3 years ago
6 0
Answer :

-5 because one negative and one positive of the same number is always 0
lana [24]3 years ago
5 0

Answer:

-5

Step-by-step explanation:

If you add 5 to -5 it will be 0 due to the - in -5. This is because negative numbers are below 0.

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3 years ago
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What is the circumference of a circle with a radius of eight inches
stira [4]

Answer:

  • 50.24 inches

\:

Step-by-step explanation:

It is given that, the radius of a circle is 8 inches and we are to find the circumference of the circle.

\:

To find the circumference of the circle we must know this formula first :

\\{ \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{  \: Circumference_{(circle)}= 2 \pi r}}}}}} \: \: \bigstar \\ \\

Where

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Now substituting the values in the formula :

\\{ \longrightarrow \qquad{  {{\sf{{  \: Circumference_{(circle)}= 2  \times 3.14 \times  8}}}}}} \: \:  \\ \\

{ \longrightarrow \qquad{  {{\sf{{  \: Circumference_{(circle)}=    3.14 \times  16}}}}}} \: \:  \\ \\

{ \longrightarrow \qquad{  { \pmb{\frak{{  \: Circumference_{(circle)}=    50.24}}}}}} \: \:  \\ \\

Therefore,

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7 0
2 years ago
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Question 1(Multiple Choice Worth 3 points)
frez [133]

Answer: D) 99 Points

Step-by-step explanation: Theresa earned scores of 88 points, 84 points, 88 points, and 91 points on four tests

Therefore the totals points are 351

351 is her total score for 4 tests, if she gets an average score of 90 on her fifth test then all we have to do is:

5 x 90 = 450 (The 5 being her fifth test)

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Option D

3 0
3 years ago
Please help me with this math problem, urgent please
Lady bird [3.3K]

Answer:

(X+2)(v-5)

Step-by-step explanation:

first, group and factor out the greatest common factor and combine to get (x+2)(v-5)

4 0
3 years ago
What is 11.876 rounded to the nearest tenth?
vesna_86 [32]

Answer:

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The tenth place is the first decimal. You round down from 1-4 and up from 5-9, so round up.

11.9

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3 years ago
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