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kotegsom [21]
3 years ago
5

Please help me with this math problem, urgent please

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
4 0

Answer:

(X+2)(v-5)

Step-by-step explanation:

first, group and factor out the greatest common factor and combine to get (x+2)(v-5)

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Which of these relations on {0, 1, 2, 3} are equivalence relations? Determine the properties of an equivalence re- lation that t
slava [35]

Answer:

The relations that are equivalence relations are a) and c)

Step-by-step explanation:

A relation on a set A is called an equivalence relation if it is reflexive, symmetric, and transitive

We are going to analyze each one.

a){ (0,0), (1,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

b){ (0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3) }

Is not an equivalence relation. Not reflexive: (1,1) is missing, not transitive: (0,2) and (2,3) are in the relation, but not (0,3)

c){ (0,0), (1,1), (1,2), (2,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

d){ (0,0), (1,1), (1,3), (2,2), (2,3), (3,1), (3,2) (3,3) }

Is not an equivalence relation. Not transitive: (1,3) and (3,2) are in the relation, but not (1,2)

e){ (0,0), (0,1) (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3) }

Is not an equivalence relation. Not symmetric: (1,2) is present, but not (2,1)Not transitive: (2,0) and (0,1) are in the relation, but not (2,1)

5 0
3 years ago
Margo’s dog, named Todd, weighed 120 pounds last year. She now weighs 180 pounds. What is the percent of change
diamong [38]

Answer:

150%

Step-by-step explanation:

3 0
3 years ago
At the craft store, Mark bought a bag of blue and brown marbles. The bag contained 20 marbles, and 30% of them were blue. How ma
kykrilka [37]

Answer:

6 blue marbles

Step-by-step explanation:

20 marbles * .30 are blue = blue marbles

20 * .30 = 6 blue marbles

5 0
3 years ago
A doctor studies the known cancer patients in a certain town. The probability that a randomly chosen resident has cancer is foun
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Let the event 'has cancer' be C, and the event 'works for Ajax' be A.
P(C) = 0.0019. P(A) = 0.28
The events A and C are independent if P(C|A) = P(C).
P(C|A) = 0.0019 = P(C).
Therefore the answer is YES.

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3 years ago
Multiply and simplify <br><br> what is 5 and 3/4 x 3 over 4 equally?
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4.3125 is the answer to that equation
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