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Svetach [21]
3 years ago
6

Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park: A coordinate plane is shown.

There is a point at negative 6, 3 labeled Dog 1. There is a point at negative 6, negative 3 labeled Dog 2. Which statement best describes the relationship between the positions of the two players? Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different. Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different. Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different. Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.
Mathematics
2 answers:
Pavel [41]3 years ago
4 0

Answer:

122453358594 hhfxmgmfkmnkmgng

Step-by-step explanation:

Plz answer meeee2 years ago
0 0

B is the answerr

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3 years ago
Help i dont know how to do this type of questions​
Scrat [10]

Answer:

x = 28°

y = 23°

Step-by-step explanation:

5y - 4 + 3y = 180

solve for y

8y = 184

y = 23

3y and 2x + 13 are equal

solve for x now that we know y is 23.

3(23) = 2x + 13

69 = 2x + 13

56 = 2x

28 = x

6 0
3 years ago
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Can you guys help me fill this out?
Nataly_w [17]

Answer: x=6

Step-by-step explanation:

2x+5= 17

    -5=-5

(subtract 5 on both side)

     2x=12

(divid 2 on each side)

x=6

5 0
3 years ago
Read 2 more answers
Prove ΔPAB is isosceles.
Licemer1 [7]

Answer:

See explanation

Step-by-step explanation:

If PX\cong PY, then triangle PXY is isosceles triangle. Angles adjacent to the base XY of an isosceles triangle PXY are congruent, so

\angle 1\cong \angle 2

and

m\angle 1=m\angle 2

Angles 1 and 3 are supplementary, so

m\angle 3=180^{\circ}-m\angle 1

Angles 2 and 4 are supplementary, so

m\angle 4=180^{\circ}-m\angle 2

By substitution property,

m\angle 4=180^{\circ}-m\angle 2=180^{\circ}-m\angle 1=m\angle 3

Hence,

\angle 3\cong \angle 4

Consider triangles APX and BPY. In these triangles:

  • PX\cong PY - given;
  • \angle 5\cong \angle 6 - given;
  • \angle 3\cong \angle 4 - proven,

so \triangle APX\cong \triangle BPY by ASA postulate.

Congruent triangles have congruent corresponding sides, then

AP\cong BP

Therefore, triangle APB is isosceles triangle (by definition).

6 0
4 years ago
For the function above, what is the missing value in the table below:
ollegr [7]
Answer- 4
U need to plug in 1 for x and solve which would be 4
7 0
3 years ago
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