Answer:
192m³
Step-by-step explanation:
This problem bothers on the mensuration of solid shapes, a square based pyramid
The highlighted figure is a square based pyramid
The volume of a pyramid is
V=a²h/3
Where a= base length
h= height
Given a= 8m
h= 9m
Volume = 8²*9/3
Volume = 64*3
Volume = 192m³
Answer:
![n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Br%7D%7B%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20-1%20%7D)
Step-by-step explanation:


![\sqrt[nt]{\frac{a}{p}} =(1+\frac{r}{n} )](https://tex.z-dn.net/?f=%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20%20%3D%281%2B%5Cfrac%7Br%7D%7Bn%7D%20%29)
![\sqrt[nt]{\frac{a}{p}} -1 =(\frac{r}{n} )](https://tex.z-dn.net/?f=%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20-1%20%3D%28%5Cfrac%7Br%7D%7Bn%7D%20%29)
![n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Br%7D%7B%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20-1%20%7D)
[ Do not confuse, as there are 2 n's, one in subject and another as power. We can never make the power or in a root, the subject. In order to solve for n, we have to make the character "n", the subject. ]
You have to find the LCD or least common denominator.
In this case the LCD would be (x-6)(x+5).
Problem: x/ x-6 - 1/x+5
Step 1: multiply x-6 to the numerator and denominator of 1/x+5
1(x-6)/ (x+5)(x-6)
Step 2: multiply x+5 to the numerator and denominator of x/x-6
x(x+5)/ (x+5)(x-6)
After all that, this is how the problem should look now
x(x+5)/ (x-6)(x+5) - 1(x-6)/ (x-6)(x+5)
If you simplify this you get
x²+5x-x+6/ (x-6)(x+5)
If you subtract both 5x-x (like terms) you get
x²+4x+6/ (x-6)(x+5)
which is the answer