6sqrt2 for both since there equivalent
A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.
rounded part is a semicircle so the area for that is the area of a circle ÷ 2
so
area of the rectangle + (area of the circle ÷ 2) = answer
24 * 14 = 336 = area of the rectangle
14 ÷ 2 = r
(pi * 7^2) ÷ 2
(pi * 49) ÷ 2 = 153.86 ÷ 2 = 76.93 = area of semicircle
336 + 76.93 = 412.93 ft^2 = answer
I believe the correct answer is 18
Answer:
What question?
Step-by-step explanation:
I don't see a question do you?
