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3 years ago

Once again... we almost finish, solve for x

Mathematics

1 answer:

algol133 years ago

3 0

Answer:

x = 34

Step-by-step explanation:

Angles are supplementary:

x + 7 + 4x + 3 = 180

5x + 10 = 180

5x = 170

x = 34

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Solve 12−5x−4kx=y for x.

IgorC [24]

Answer:

x = $\frac{12-y}{4k+5}$

Step-by-step explanation:

12-5x-4kx=y

1. Subtract 12 from both sides.

2.Distrubutive property (factor) a(b+c)=ab+ac

x(-5-4k)=y-12

Divide by -5-4k

x = $\frac{y-12}{-5-4k}$

= $\frac{12-y}{4k+5}$

5 0

3 years ago

I don’t really get this question can someone help me out

Inessa [10]

angles EFH and GFH are congruents

for the second equivalence criterion two triangles are equivalents if they have respectively 2 angles and 1 side congruents

the two triangles have congruents the angle right angle (HGF and HEF) and the 55 degrees angles (EFH and GFH); then they have in common the HF side.

so the triangles are congruent and so all the sides are respectively congruent,for example EH with HG:

EH=HG

s+36=7s

s+36-7s=0

s-7s=-36

-6s=-36

6s=36

s=6

<em>sorry for my english</em>

5 0

4 years ago

What integer increased by - 12 is 28?

guajiro [1.7K]

Answer:

Step-by-step explanation:

Let n represent the integer. Then the increase can be written as ...

n + (-12) = 28

We can add 12 to both sides of this equation:

n + (-12) + (+12) = 28 +12

n + 0 = 40 . . . . . . -12 and 12 total to zero; 28 and 12 total to 40.

n = 40

The integer is 40.

4 0

3 years ago

Please help pic is included

den301095 [7]

The answer to Ur ? is -2

4 0

3 years ago

From A to B a private plane flies 2.8 hours at 110 mph on a bearing of 64 degrees . It turns at point B and continues another 1.

Firdavs [7]

Answer:

a. 360.323 m

b. $95.265^{o}$

Step-by-step explanation:

Distance covered from A to B = speed x time

= 110 x 2.8

= 308 m

Distance covered from B to C = speed x time

= 110 x 1.7

= 187 m

The sum of angles at B = $64^{o}$ + $26^{o}$

= $90^{o}$

a. The distance of the plane from it starting point to C can be determined by applying the cosine rule.

$b^{2}$ = $a^{2}$ + $c^{2}$ - 2ac Cos B

Sot hat;

$b^{2}$ = $187^{2}$ + $308^{2}$ - 2(187 x 308) Cos $90^{o}$

But, Cos $90^{o}$ = 0

So that,

$b^{2}$ = $187^{2}$ + $308^{2}$

= 34969 + 94864

= 129833

b = $\sqrt{129833}$

= 360.323

The distance from A to C is 360.323 m.

b. Applying the sine rule;

$\frac{a}{SinA}$ = $\frac{b}{SinB}$

$\frac{187}{SinA}$ = $\frac{360.323}{Sin90^{o} }$

$\frac{187}{SinA}$ = $\frac{360.323}{1}$

Sin A = $\frac{187}{360.323}$

= 0.5190

⇒ A = $Sin^{-1}$ 0.5190

= $31.265^{o}$

The bearing of the plane from its original location = $64^{o}$ + $31.265^{o}$

= $95.265^{o}$

8 0

3 years ago