- increasing the concentration of N₂
- increasing the concentration of O₂
- decreasing the concentration of NO
- increasing the temperature
:)
Answer:
B. It has a stable octet and is unreactive.
Explanation:
s orbital contains 2 electrons and p contains 6. When the outermost energy level of an element has a total of 8 electrons we call it stable octet and it is unreactive. Therefore the answer is B
Answer:
There is 26.58 grams of gold formed
Explanation:
Step 1: Data given
17.6 A of current are passed through a gold solution for 37.0 min
Molar mass of Au = 196.967 g/mol
Step 2: The equation
Au^3+ + 3e- → Au
Step 3: Calculate coulombs
17.6 Coulomb/s * 37.0 min * 60 sec/min = 39072 Coulombs
1 Faraday = 96500 Coulombs
Step 4: Calculate faraday
39072 Coulombs / 96500 Coulombs / Faraday = 0.40489 Faraday
Step 5: Calculate mass of gold formed
For every 3 Faraday of electricity used up , 1 mole Au is formed
0.40489 Faraday * 1 mole Au/ 3 Faraday = 0.13496 mole Au
196.967 g/mol * 0.13496 mol = 26.58 g Au
There is 26.58 grams of gold formed
The formula of Washing Soda is (Na2CO3.10H2O). It contains two atoms of Sodium,one atom of Carbon, thirteen atoms of Oxygen and twenty atoms of Hydrogen.
It's chemical name is Sodium Carbonate decahydrate. It is white coloured crystal which is basic in nature. So, it is called a basic salt. It turns red litmus paper into blue.
Mass after 60 years:
2 kg of cesium-137 will remain after 60.0 years.
What is Half-life?
The duration needed for a quantity to decrease to half of its initial value is known as the half-life.
Given:
N0 = is the initial amount of cesium-137 = 8.0 Kg
N = is the amount remaining after a time = Unknown
t = Duration of cesium-137 decay in 8.0 Kg = 60 years
t1/2 = half-life of cesium-137 = 30.0 years
Formula = N/No = (1/2)^t/t1/2
After putting the value:
N/8= (1/2)^60/30
N/8= (1/2)^2
N/8= 1/4
4N= 8
N= 8/4
N= 2 Kg
As a result, 2 Kg of cesium-137 will be present after 60 years.
Learn more about the half-life here,
brainly.com/question/14018709
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