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Lelu [443]
3 years ago
12

The work done to compress a gas is 83.0 J. As a result, 27.0 J of heat is given off to the surroundings. Calculate the change in

energy of the gas.
Chemistry
1 answer:
stellarik [79]3 years ago
5 0

Answer:

ΔU° = 56.0 J

Explanation:

Step 1: Given data

  • Work done to compress the gas (w): 83.0 J (When work is done on the gas, w is positive).
  • Heat given off to the surroundings (q): -27.0 J (When heat is released to the surroundings, q is negative)

Step 2: Calculate the change in the internal energy of the gas (ΔU°)

The internal energy of a gas is the energy contained within it. We can calculate it using the following expression.

ΔU° = q + w

ΔU° = -27.0 J + 83.0 J

ΔU° = 56.0 J

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The kinetic energy of a 10.3 g golf ball traveling at 48.0 m/s is
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E = 0.5 x (mass) x (velocity)^2


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3 0
3 years ago
Which of the following buffers will be most effective at pH 9.25? Group of answer choices a mixture of 1.0 M HC2H3O2 and 1.0 M N
ludmilkaskok [199]

Answer:

The most effective buffer at pH 9.25 will be  a mixture of 1.0 M NH3 and 1.0 M NH4Cl

Explanation:

Step 1: Data given

pH of a buffer = pKa + log ([A-]/[Ha])

a mixture of 1.0 M HC2H3O2 and 1.0 M NaC2H3O2 (Ka for acetic acid = 1.8 x 10-5)

pH = -log( 1.8 * 10^-5) + log (1/1)

pH = -log( 1.8 * 10^-5)

pH = 4.74

a mixture of 1.0 M NaCN and 1.0 M KCN (Ka for HCN = 4.9 x 10-10)

pH = -log( 4.9 * 10^-10) + log (1/1)

pH = -log( 1.8 * 10^-5)

pH = 9.30

a mixture of 1.0 M HCl and 1.0 M NaCl

The solution made from NaCl and HCl will NOT act as a buffer.

HCl is a strong acid while NaCl is salt of strong acid and strong base which do not from buffer solutions hence due to HCl PH is less than 7.

a mixture of 1.0 M NH3 and 1.0 M NH4Cl (Kb for ammonia = 1.76 x 10^-5)

Ka * Kb = 1*10^-14

Ka = 10^-14 / 1.76*10^-5

Ka = 5.68*10^-10

pH = -log( 5.68*10^-10) + log (1/1)

pH = -log( 5.68*10^-10)

pH = 9.25

The most effective buffer at pH 9.25 will be  a mixture of 1.0 M NH3 and 1.0 M NH4Cl

8 0
2 years ago
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