Answer:
C is the answers for the question
Answer:
C. y = 3/5x + 13/5
Step-by-step explanation:
<u>Solution-</u>
Zachary purchased a computer for 1800 on a payment plan. (Initial Money)
3 months after he bought the computer, his balance was 1350. (Money after 3 months)
Total money paid in 3 months = 1800-1350 = 450
Money paid per month = 450/3 = 150
5 months after he bought the computer, his balance was 1050.
Total spent = 1800-1050 = 750 = (5× 150)
So the equation that models the balance b after m months,
b = 1800 - m(150)
∴ Here, the slope signifies the constant monthly deduction of $150.
The height of your scale model will be 37.8cm.
1.26 x 30
Answer:
The solution of this expression is
and
.
Step-by-step explanation:
The procedure for solution of exercise A is described below:
1) We expand the expression.
2) The resulting expression is rearranged into the form of a second order polynomial.
3) Roots are found by Quadratic Formula.
Step 1:



Step 2:

Step 3:



The solution of this expression is
and
.