$t = k \frac{1}{s} \\ 2 = k. \frac{1}{60} \\ k = 120 \\ k \: \: is \: constant \: of \: variation \\ relationship \: is \\ t = \frac{120}{s} . \\ when \: s \: = 90 \\ t = \frac{120}{90} \\ t = \frac{4}{3} \\ when \: t = 2 \frac{1}{2} \\ s = \frac{120}{2 \frac{1}{2} } \\ s = 48$

4 0

3 years ago

Least to greatest -.6 -5/8 -7/12 -.72

svlad2 [7]

It would be:

-.72 < -5/8 < -.6 < -7/12

4 0

3 years ago

What is the distance between –3 and 2 on the number line?A: –5<br> B:–1<br> C:1<br> D:5

madreJ [45]

Your answer would be D.) 5

6 0

3 years ago

Read 2 more answers

at the dog show, there are 4 times as many boxer as spaniels. if there are a total of 30 dogs, how many dogs are spaniel?

Lyrx [107]

Firstly, given this information there could be 25 labradors and poodles and only 4 boxers and 1 spaniel. However, assuming that there are only boxers and spaniels at the dog show the first thing to do is to divide 30 by 5 = 6 so the answer is, There are 6 spaniels.

5 0

3 years ago