We need to know the function that models the difference in the number of customers visiting the two stores.
We know the function that models the number of customers in the cafeteria
W (x) = 0.002x3 - 0.01x2
We also know the function that models the number of customers who visit the ice cream parlor
R (x) = x2 - 4x + 13
Therefore the difference, D (x), in the number of customers visiting the two stores is:
D (x) = W (x) - R (x)
D (x) = 0.002x ^ 3 - 0.01x ^ 2 - (x ^ 2 -4x +13)
D (x) = 0.002x ^ 3 - 0.01x ^ 2 - x ^ 2 + 4x -13

D (x) = 0.002x ^ 3 - 1.01x ^ 2 + 4x -13
 The answer is the third option

8 0

3 years ago

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Resolve into partial fractions

lisabon 2012 [21]

Answer:

See below

Step-by-step explanation:

$\frac{11 + x}{(2 - x)(x - 3)} = \frac{A}{2 - x} + \frac{B}{x - 3} \\ \\ \therefore \: \frac{11 + x}{(2 - x)(x - 3)} = \frac{A(x - 3) +B(2 - x) }{(2 - x)(x - 3)} \\ \\ \therefore \: 11 + x = Ax - 3A + 2B - Bx \\ \\ \therefore \: 11 + x = - 3A + 2B + Ax - Bx\\ \\ \therefore \: 11 + x = - 3A + 2B + (A - B)x \\ \\ equating \: the \: like \: terms \: on \: both \: sides \\ A - B = 1 \\ \therefore \: A = B + 1.....(1) \\ \\ - 3A + 2B = 11....(2) \\ from \: eq \: (1) \: and \: (2) \\ - 3(B + 1) + + 2B = 11 \\ \\ - 3B - 3 + 2B = 11 \\ \\ - B = 11 + 3 \\ \\ B = - 14 \\ A = - 14 + 1 = - 13 \\ \\ \frac{11 + x}{(2 - x)(x - 3)} = \frac{ - 13}{2 - x} + \frac{ - 14}{x - 3} \\ \\ \frac{11 + x}{(2 - x)(x - 3)} = - \frac{ 13}{2 - x} - \frac{ 14}{x - 3}$

$\frac{12x + 11}{x^2 +x - 6}$

$=\frac{12x + 11}{x^2 +3x-2x - 6}$

$=\frac{12x + 11}{x(x +3) -2(x +3)}$

$\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{12x + 11}{(x +3) (x - 2)}$

$\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A}{(x +3)}+\frac{B}{(x - 2)}$

$\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A(x-2)+B(x+3)}{(x-2)(x+3)}$

$\therefore 12x + 11 = A(x-2)+B(x+3)$

$\therefore 12x + 11 = Ax-2A+Bx+3B$

$\therefore 12x + 11 = Ax+Bx-2A+3B$

$\therefore 12x + 11 = (A+B) x-2A+3B$

Equating like terms on both sides:

$A + B = 12\implies A = 12-B... (1)$

$- 2A + 3B = 11... (2)$

Solving equations (1) & (2), we find:

A = 5, B = 7

$\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{5}{(x +3)}+\frac{7}{(x - 2)}$

3 0

3 years ago

On a unit circle, the terminal point of 0 is (sqrt3/2,1/2) What is 0?

san4es73 [151]

Answer:

The measure of $\theta$ is 30°.

Step-by-step explanation:

In the statement, the angle has been misrepresented. The corrected statement is described below:

"On a unit circle, the terminal point of $\theta$ is $\left(\frac{\sqrt{3}}{2}, \frac{1}{2} \right)$ . What is $\theta$ ?"

The measure of the angle ( $\theta$ ), in radians, is in standard form, that is, it is done with respect to the +x semiaxis. The measure of the angle whose terminal point is of the form $(x,y)$ is determined by the following inverse trigonometric function: